The answer is 23 units
I wrote a solution, if you don't understand anything, just ask:)
Answer:
33.6, 39, 61. That's without knowing these numbers
Answer:42
Step-by-step explanation:
Because 7 times 3 is 21 so then you'll times 7 by the other 3 and 21+21=42
Answer:
Probability that their mean is above 215 is 0.0287.
Step-by-step explanation:
We are given that a bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviation of 50.
For this, 40 different applicants are randomly selected.
<em>Let X = ratings for credit</em>
So, X ~ N(
)
Now, the z score probability distribution for sample mean is given by;
Z =
~ N(0,1)
where,
= population mean = 200
= standard deviation = 50
= sample mean
n = sample of applicants = 40
So, probability that their mean is above 215 is given by = P(
> 215)
P(
> 215) = P(
>
) = P(Z > 1.897) = 1 - P(Z
1.897)
= 1 - 0.97108 = 0.0287
Therefore, probability that their mean is above 215 is 0.0287.
Answer:
(1) ΔMAN ≅ ΔBOY
(2) ΔMAT ≅ ΔRUG
(3) ΔEBN ≅ ΔUHR
(4) ΔTOP ≅ ΔLID
(5) ΔCAT ≅ ΔDOG
(6) ΔITP ≅ ΔLOH
Step-by-step explanation:
The following combinations of the congruent triangle facts will be sufficient to prove triangles congruent.
The combinations are:
(1) SSS (side-side-side) : If three sides of a triangle are congruent to three sides of another triangle then the triangles are congruent.
(2) SAS (side-angle-side) : If two sides and included angle of a triangle are congruent to another triangle then the triangles are congruent.
(3) ASA (angle-side-angle) : If two angles and included side of a triangle are congruent to another triangle then the triangles are congruent.
(4) RHS (right angle-hypotenuse-side) : If the hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle, the right triangles are congruent.
Part (1):
As we are given two triangles.
Side AM = Side OB
Side MN = Side BY
Side AN = Side OY
That means,
ΔMAN ≅ ΔBOY
Part (2):
As we are given two triangles.
Side MA = Side RU
Side MT = Side RG
Side AT = Side UG
That means,
ΔMAT ≅ ΔRUG
Part (3):
As we are given two triangles.
Side EB = Side UH
Side BN = Side HR
Side NE = Side RU
That means,
ΔEBN ≅ ΔUHR
Part (4):
As we are given two triangles.
Side OT = Side IL
Side OP = Side ID
Side PT = Side DL
That means,
ΔTOP ≅ ΔLID
Part (5):
As we are given two triangles.
Side AC = Side OD
Side AT = Side OG
Side TC = Side GD
That means,
ΔCAT ≅ ΔDOG
Part (6):
As we are given two triangles.
Side TP = Side OH
Side IT = Side LO
Side IP = Side LH
That means,
ΔITP ≅ ΔLOH