Three quadratic equations that have one real solution are show below:
5x^2+3x^3+3^4 = 55
5x^2+3x^3+3^7 = 55
5x^2+3x^3+3^8 = 55
The lesser x is 2 and the greater x is 3. The x values can be determined by setting each set of numbers in parenthesis equal to 0, so 3x-6=0 and -x+3=0. To solve, take the first set, 3x-6=0 and divide by the greatest common factor, 3, leaving you with x-2=0. Add 2 to each side so that x=2. On the other side, take -x+3=0 and subtract three from each side. Take your new equation -x=-3 and multiply by -1 so that x=3. Therefore x=3 and x=2.
The angle measures tell you the triangles are similar, so corresponding sides will have the same ratio.
GX/BX = UH/NH
GX = BX·UH/NH
GX = 7·18/(3√11)
GX = (42/11)√11
GB/BX = UN/NH
GB = BX·UN/NH
GB = 7·15/(3√11)
GB = (35/11)√11
4*130%=5.2
7*130%=9.1
5.2*2+9.1*2=28.6 in
or You can just do
(4+7)*130%*2=28.6 in
