Please help me with this question

Mathematics

1 answer:

Stels [109]3 years ago

7 0

I believe it is answer number 3

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What are the solutions to the equation 2x^2 - 2x - 12 = 0?

pantera1 [17]

2(x)^2 - 2(x) - 12 = ?

2(x)^2 - 2(x) - 12

(x)^2 - 6 - x

Multiply ↪1 (-6) = -6

1 + -6 = -5 , right?

-3 + 2 = -1, right?

After we have pulled out the like terms we have to add/subtract!   x(x) - 3

Search for the common denominator
2(x) - 3

You can add up 4 for your terms
x + 2 (x - 3)

Make sure you solve this↪ 2 = 0

x + 2 = ?
x + 2 = 0
We have found the first; x = -2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Since, this one has a single variable, I'll make the step easier and quicker

Solve this part ↪    x-3 = 0
If we had the number 3 to your sides we would have found the outcome of the next x

So, the second x is 3

So, therefore your answer would have to be x =-2 ; x = 3 (most likely option C.)

5 0

3 years ago

A class committee is to be made that consists of 2 freshmen, 2 sophomores, 3 juniors, and 3 seniors. If students are being rando

GuDViN [60]

$C(12,2)\cdotC(17,2)\cdotC(16,3)\cdotC(20,3)=\\\\\dfrac{12!}{2!10!}\cdot\dfrac{17!}{2!15!}\cdot\dfrac{16!}{3!13!}\cdot\dfrac{20!}{3!17!}=\\\\\dfrac{11\cdot12}{2}\cdot\dfrac{16\cdot17}{2}\cdot\dfrac{14\cdot15\cdot16}{2\cdot3}+\dfrac{18\cdot19\cdot20}{2\cdot3}=\\\\66\cdot136\cdot560\cdot1140=5,730,278,400$