Find the surface of the prism

What part of 40 is 16?

Anit [1.1K]

Answer:

56

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> 100(1.21)x = 110

SVETLANKA909090 [29]

Answer:X=110/121

Step-by-step explanation:

Multiply 100 by 1.21 then by x

121x=110

Divide both side by 121

X=110/121

X=0.91

8 0

3 years ago

Order from least to greatest

Dafna1 [17]

3.75, 3.9, 4.256, 4.258, 4.5

3 0

3 years ago

Mrs. Wigen conducted a survey in her math class. She asked each of her students to tell her how many pets they have at home. The

Lera25 [3.4K]

Answer:

4 : 25 to round off we have to see that

4 : 25 to round off we have to see that If in ones place it is more than 5 or not

4 : 25 to round off we have to see that If in ones place it is more than 5 or not if yes we will add to 1 no to tenths place

4 : 25 to round off we have to see that If in ones place it is more than 5 or not if yes we will add to 1 no to tenths place Finally 4 : 25 it has 5 in its ones place

<h3><em><u>So the answer will be 4 : 30</u></em> </h3>

7 0

3 years ago

To illustrate the effects of driving under the influence (DUI) of alcohol, a police officer brought a DUI simulator to a local h

Oksanka [162]

Answer:

a) If we design the experiment on this way we can check if we have an improvement with the method used.

We assume that we have the same individual and we take a value before with the normal impaired condition and the final condition is the normal case.

b) $-0.96-2.306\frac{0.359}{\sqrt{9}}=-1.24$

$-0.96+2.306\frac{0.359}{\sqrt{9}}=-0.69$

The 95% confidence interval would be given by (-1.24;-0.69)

Step-by-step explanation:

Part a

If we design the experiment on this way we can check if we have an improvement with the method used.

We assume that we have the same individual and we take a value before with the normal impaired condition and the final condition is the normal case.

Part b

For this case first we need to find the differences like this :

Normal, Xi 4.47 4.24 4.58 4.65 4.31 4.80 4.55 5.00 4.79

Impaired, Yi 5.77 5.67 5.51 5.32 5.83 5.49 5.23 5.61 5.6

Let $d_i = Normal -Impaired$

$d_i : -1.3, -1.43, -0.93, -0.67,-1.52, -0.69, -0.68, -0.61, -0.81$

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}=-0.96$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =0.359$

The confidence interval for the mean is given by the following formula:

$\bar d \pm t_{\alpha/2}\frac{s_d}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=9-1=8$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that $t_{\alpha/2}=2.306$

Now we have everything in order to replace into formula (1):

$-0.96-2.306\frac{0.359}{\sqrt{9}}=-1.24$

$-0.96+2.306\frac{0.359}{\sqrt{9}}=-0.69$

So on this case the 95% confidence interval would be given by (-1.24;-0.69)

6 0

3 years ago