PLS HELP ME this is due today thank u.
2 answers:
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Answer:
<ABC = (The central angle of a circle is twice any inscribed angle subtended by the same arc).
Step-by-step explanation:
From the diagram, ABC is an inscribed isosceles triangle. But the radius of the circle equals the length AC.
Join P to A and C to form an equilateral triangle. An equilateral triangle has equal sides and angles. So, the value of each interior angle of the equilateral triangle is;
Sum of angle in a triangle =
So that each interior angle =
=
The value of each interior angle of the triangle is . Thus, <APC =
.
⇒ <ABC = (The central angle of a circle is twice any inscribed angle subtended by the same arc.)
Answer:
12.53
Step-by-step explanation:
∠BCA = (180°-40°)/2 = 70°
Laws of Sines: CA/sin 40° = AB/sin 70° = 5/sin 70°
CA = 5/sin 70° * sin 40° = 3.40
area of semicircle CA = (3.1416 * 1.70²) / 2 = 4.54
By Heron's Formula, area of triangle ABC:
1/4 √(a+b+c) (a+b-c) (b+c-a) (c+a-b) = 1/4 * √13.4*3.4*3.4*6.6
= 7.99
Entire region area = 4.54 + 7.99 = 12.53
