Answer:
It would be 28 brazilian and 4 Colombian
Step-by-step explanation:
I multiplied alot and please forgive me if this is wrong
They have a period so the decimals
This is an inequality.
This is what the statement should look like: ![57 > x - 8](https://tex.z-dn.net/?f=57%20%3E%20x%20-%208)
Now, you can actually "properly" reverse these meaning the equality sign changes too. So basically you can mirror them.
The "mirrored" inequality expression would look like this: ![x - 8 < 57](https://tex.z-dn.net/?f=x%20-%208%20%3C%2057)
Now just like normal algebra, you can transpose these terms from 1 side to another and so, -8 would transpose to the right hand side and the operation would be the inverse or in this case, addition. The expression would look something like this: ![x < 57 + 8](https://tex.z-dn.net/?f=x%20%3C%2057%20%2B%208)
Add them up and you get:
:D
Answer:
Cubr is very mahirap na sagutin
Answer: ![96\pi\text{ units}^2](https://tex.z-dn.net/?f=96%5Cpi%5Ctext%7B%20units%7D%5E2)
Step-by-step explanation:
From the given picture, it can be seen that the radius of the circle = 16 units
Also, the measure of central angle XYZ
radians
The area of sector with radius r and angle x radian is given by :-
![\text{Area of sector}=\dfrac{1}{2}r^2\ x](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20sector%7D%3D%5Cdfrac%7B1%7D%7B2%7Dr%5E2%5C%20x)
Now, the area of the shaded sector is given by :-
![\text{Area of the shaded sector}=\dfrac{1}{2}(16)^2\dfrac{3}{4}\pi\\\\\Rightarrow\text{Area of the shaded sector}=96\pi\text{ units^2}](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20shaded%20sector%7D%3D%5Cdfrac%7B1%7D%7B2%7D%2816%29%5E2%5Cdfrac%7B3%7D%7B4%7D%5Cpi%5C%5C%5C%5C%5CRightarrow%5Ctext%7BArea%20of%20the%20shaded%20sector%7D%3D96%5Cpi%5Ctext%7B%20units%5E2%7D)