Answer:
22
Step-by-step explanation:
Answer:
The correct option is;
2.81
Step-by-step explanation:
The critical value
, is found from the z score table as follows, where the the confidence level is 99.5
Therefore, we have α = 1 - 99.5/100 = 1 - 0.995 = 0.005
α/2 = 0.0025
The critical value is thus found from the z-score table value of 1 - 0.0025 = 0.9975
From the z-table, we can find the 0.9975 score on the row with z = 2.8 where 0.9975 can be located under the 0.1 column giving the critical value as 2.81
The answer to the question is B
The function is
![f(x) = \begin{cases} x^2-4 &\mbox{if } x\ \textless \ 1, \\ x+4 & \mbox{if } x\ \textgreater \ 1. \end{cases}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cbegin%7Bcases%7D%20x%5E2-4%20%26%5Cmbox%7Bif%20%7D%20x%5C%20%5Ctextless%20%5C%201%2C%20%5C%5C%20%0Ax%2B4%20%26%20%5Cmbox%7Bif%20%7D%20x%5C%20%5Ctextgreater%20%5C%201.%20%5Cend%7Bcases%7D)
.
To the left of 1 the function is a quadratic polynomial, to the right, it is a linear polynomial. Polynomial functions are always continuous, so the only candidate point for discontinuity is x=1.
The left limit is calculated with 1 substituted in
![x^2+4](https://tex.z-dn.net/?f=x%5E2%2B4)
, which gives 5.
The right limit, is computed using the rule for the right part of 1, that is x+4.
Thus, the right limit is 1+4=5.
So, both left and right limits are equal. Now if f(1) is 5, then the function is continuous at 1.
But the function is not defined for x=1, that is x=1 is not in the domain of the function. Thus, we have a "whole" (a discontinuity) in the graph of the function.
The reason is now clear:
Answer:<span> f(1) is not defined</span>
Answer:
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Step-by-step explanation:
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