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Veseljchak [2.6K]

3 years ago

7

,,,,,,,,,hi help pls

1 answer:

aliya0001 [1]3 years ago

4 0

Answer: slope is 0
to find the slope , you have to subtract y-es and divide them by x-es.(delta y/ delta x)
so,
(-6,-2) (-7,-2)
slope: -2-(-2)/-7-(-6)
slope:0/ -1
slope: 0
which looks on the graph like this:

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Can someone help me ?<br> A. -12<br> B. -6<br> C. 0<br> D. 12

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Larry has saved $18,500 toward a down payment on a house. If he makes $3,890 a month , how much can he afford to spend on house?

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I'm pretty sure the answer is D

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The average NCAA basketball team has 16 players.Two-fiths of the team are an odd number.How many players are a even number?

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3 years ago

A large tank is filled to capacity with 300 gallons of pure water. Brine containing 5 pounds of salt per gallon is pumped into t

Gwar [14]

Answer:

(a) $A = 1500(1 - e^{-0.01t})$

(b) $t = 0$

Step-by-step explanation:

Given

$V= 300gal$ --- Volume of tank

$B = 5lb/gal$ --- Brine solution

$R_1 = 3gal/min$ --- Rate in, in gallon/min

$R_2 = 6gal/min$ --- Rate out, in gallon/min

Required

Determine A(t)

First, calculate the rate in (R in) and (R out) in lb/min

$R_{in} = B * R_1$

$R_{in} = 5lb/gal * 3gal/min$

$R_{in} = 15lb/min$

R(out) is calculated by multiply the rate at which brine leaves the tank (lb/gal) * R2

So, we have:

$R_{out} = \frac{A(t)}{300} lb/gal * 3gal/min$

$R_{out} = \frac{3*A(t)}{300} lb/min$

$R_{out} = \frac{A(t)}{100} lb/min$

The change in the amount of brin e in the tank at time t is given as:

$A'(t) = R_{in} - R_{out}$

$A'(t) = 15 - \frac{A(t)}{100}$

Rewrite:

$\frac{dA}{dt} = 15 - \frac{A}{100}$

Multiply through by dt

$dA = [15 - \frac{A}{100}]* dt$

Make dt stand alone

$\frac{dA}{15 - \frac{A}{100}} = dt$

$ln|15 - \frac{A}{100}| = -0.01t + ln\ c$

Express as exponents

$15 - \frac{A}{100} = ce^{-\frac{t}{100}}$

Multiply through by 100

$1500 - A = 100ce^{-\frac{t}{100}}$

$A = 1500 - 100ce^{-\frac{t}{100}}$

$A = 1500 - 100ce^{-0.01t}$

Apply initial conditions

$A(0) = 0$

Substitute 0 for t in: $A = 1500 - 100ce^{-0.01t}$

$0 = 1500 - 100ce^{-0.01*0}$

$0 = 1500 - 100ce^{0}$

$0 = 1500 - 100c$

$100c = 1500$

$c = 15$

Substitute 15 for c in $A = 1500 - 100ce^{-0.01t}$

$A = 1500 - 100*15e^{-0.01t}$

$A = 1500 - 1500e^{-0.01t}$

Factorize:

$A = 1500(1 - e^{-0.01t})$

How long to empty the tank

Set A to 0

$1500(1 - e^{-0.01t}) = 0$

Divide through by 1500

$1 - e^{-0.01t} = 0$

Collect Like Terms

$e^{-0.01t} = 1$

Take ln of both sides

$ln\ (e^{-0.01t}) = ln\ 1$

$-0.0t = 0$

$t = 0$

8 0

3 years ago

Given that B, D and F are midpoints, find the length of segment DA.

TiliK225 [7]

Answer:

The length of segment DA is 15 units

Step-by-step explanation:

<em>The segment which joining a vertex of a triangle and the midpoint of the opposite side to this vertex is called a median </em>

<em>The point of intersection of the median of a triangle divides each median into two parts the ratio between them is 1: 2 from the base, which means </em><em>the length of the median is 3 times the part from the base</em><em> </em>

Let us use this rule to solve the question

In Δ AEC

∵ D is the midpoint of EC

∴ AD is a median

∵ B is the midpoint of AC

∴ EB is a median

∵ F is the midpoint of AE

∴ CF is a median

→ The three medians intersected at a point inside the triangle,

let us called it M

∵ AD ∩ EB ∩ CF at M

∴ M is the point of intersection of the medians of Δ AEC

→ By using the rule above

∴ AD = 3 MD

∵ MD = 5

∴ AD = 3(5)

∴ AD = 15 units

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3 years ago

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