Area of a rectangular barnyard: A=6x^2+7x-20
A=6(6x^2+7x-20)/6
A=[(6^2)(x^2)+7(6x)-120]/6
A=[(6x)^2+7(6x)-120]/6
A=(6x+15)(6x-8)/6
A=(6x+15)(6x-8)/[(3)(2)]
A=(6x/3+15/3)(6x/2-8/2)
A=(2x+5)(3x-4)
A=bh
b=2x+5; h=3x-4
Answer: The possible dimensions of the barnyard are 2x+5 and 3x-4
Aubrey plays for 150 minutes on the playground.
I am pretty sure that the median is 80, correct me if I'm wrong :)
Answer:
The work is on the picture
sorry was not letting write the work here
Step-by-step explanation:
Answer:
Step-by-step explanation:
for IV you do 40^2+30^2=c, or 1600+ 900=c. c= 2500 and unsquare that you get 50