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3 years ago

I need the work Plz help!

Mathematics

1 answer:

zysi [14]3 years ago

4 0

Answer:

Yes

Step-by-step explanation:

In the first equation, sub in (-3x/2) for y:

3x+4y=12

3x+4(-3x/2)=12

3x-(12x/2)=12

3x-6x=12

-3x=12

x=-4

y=-3x/2

y=-3(-4)/2

y=12/2

y=6

Since x=-4 and y=6, (-4,6) is a solution.

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Licemer1 [7]

i think that's letter B & C

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3 years ago

Read 2 more answers

Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?

garik1379 [7]

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is $z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)$ .

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be $z (x) = \cos x$ the base formula, where $x$ is measured in sexagesimal degrees. This expression must be transformed by using the following data:

$T = 180^{\circ}$ (Period)

$z_{min} = -4$ (Minimum)

$z_{max} = 5$ (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of $2\pi$ radians. In addition, the following considerations must be taken into account for transformations:

1) $x$ must be replaced by $\frac{2\pi\cdot x}{180^{\circ}}$ . (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

$\Delta z = \frac{z_{max}-z_{min}}{2}$

$\Delta z = \frac{5+4}{2}$

$\Delta z = \frac{9}{2}$

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

$z_{m} = \frac{z_{min}+z_{max}}{2}$

$z_{m} = \frac{1}{2}$

The new function is:

$z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)$

Given that $z_{m} = \frac{1}{2}$ , $\Delta z = \frac{9}{2}$ and $T = 180^{\circ}$ , the outcome is:

$z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)$

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

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3 years ago

I quite don’t get this question and I have 4 minutes remaining

gregori [183]

The length of one of the sides of the larger pentagon is 24 cm. The length of one of the sides of the smaller pentagon is 8 cm.

$24$ ÷ $8=3$

So, if the larger pentagon is 3x the size of the smaller pentagon, we can find the area of the smaller pentagon by dividing the area of the larger pentagon by 3.

$135$ ÷ $3=45$