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3 years ago

15

How do I expand and evaluate (-1.1) to the 3rd power

1 answer:

Leto [7]3 years ago

4 0

-1.331. -1.1 * -1.1 * -1.1

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The sum of two numbers is 12. The first number,x, is twice the second number ,y,

vlada-n [284]

Judging by the question at hand I generated this equation.
x+y=12
x=2y

I begin this question by plugging in the x=2y into the equation for x.
So the new equation should be 3y=12. I then divide the entire equation by 3 to get y=4.

Next I plug y=4 into the equation, the new equation should be x+4=12. I then subtract 4 from both sides to get x=8.

The two numbers are :
x=8 y=4

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4 years ago

Can someone put this in order

zaharov [31]

The first has value 2500*(1+.05*9)=3625. The second, similarly, has value 4160, and the third, 3400. Thus, the order, from least to greatest, is third, first, second.

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3 years ago

Is it 1 solution, no solution or infinite solution? <br> -28 = -7(3x + 4) + 21

prohojiy [21]

x = 1 because -7(3x + 4) must be -49 so 3x + 4 must me 7 so x = 1

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4 years ago

Solve the following equation for the variable indicated<br> 15 = Зn + 6р, for n

Taya2010 [7]

Answer:

Solving the equation $15 = 3n + 6p$ for variable n we get $\mathbf{n=5-2p}$

Step-by-step explanation:

We need to solve the equation $15 = 3n + 6p$ for variable n

Solving:

$15 = 3n + 6p$

Subtract both sides by 6p

$15-6p = 3n +6p -6p\\15-6p=3n$

Switch sides of equality

$3n=15-6p$

Divide both sides by 3

$\frac{3n}{3} =\frac{15-6p}{3}\\n=\frac{3(5-2p)}{3}\\n=5-2p$

So, solving the equation $15 = 3n + 6p$ for variable n we get $\mathbf{n=5-2p}$

8 0

3 years ago

What are the coordinates of R' for the dilation D(0.5. p)(PQRS)?

11111nata11111 [884]

Answer:

$R' = (-1,-0.5)$

Step-by-step explanation:

See attachment for complete question.

From the attachment:

$P = (-3,-3)$

$R = (1,2)$

Dilation:

$D_{(0.5,P)}$

Required

Determine R'

First, subtract the coordinates of P from R. This means that R is measured from P.

$R = (1-(-3),2-(-3))$

$R = (1+3,2+3)$

$R = (4,5)$

Next, apply dilation factor 0.5

$R' = R * 0.5$

$R' = (4,5) * 0.5$

$R' = (4* 0.5,5* 0.5)$

$R' = (2,2.5)$

Lastly, measure R' from the origin by adding the coordinates of P to R'

$R' = (2+(-3),2.5+(-3))$

$R' = (2-3,2.5-3)$

$R' = (-1,-0.5)$

6 0

3 years ago