Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as
n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) = 
= 
= 
= 
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
Answer:
13r²(2rs + 4r³ - 3s⁴)
Step-by-step explanation:
In equation 26r³s + 52r⁵ - 39r²s⁴;
The GCF of 26, 52, and 39 = 13
The GCF of r³, r⁵ and r² = r²
The GCF of s, (no "s"), and s⁴ = no "s" (Since one of the number doesn't have "s")
Now we can factor out 13r² from all three expressions;
26r³s + 52r⁵ - 39r²s⁴
=> <em>13r²(2rs) + 13r²(4r³) - 13r²(3s⁴)</em>
To factor it all together;
<u>13r²(2rs + 4r³ - 3s⁴)</u>
Hope this helps!
Answer:
121
Step-by-step explanation:
The missing number is 121. I got this by doing 764-130-513=121. You would do this because you are trying to find the number that would allow 130 and 513 to add up to 764.
Another way to look at this problem is 513+130= 643
764-643=121
In conclusion, 513+121+130=764
Answer:
increasing
Step-by-step explanation:
Since the line goes up from left to right, the graph is increasing
Answer:
Q= 126°
Step-by-step explanation:
Using the picture given, because these are parallel lines broken by a transversal, we can say the following
M=A=Q=F
B=C=D=G
Since, for example, M and C are the same line, we can say that M+C=180 and so on.
M=Q
Q= 126°
