Answer:
-19 1/9
Step-by-step explanation:
Answer:
The answers are a, and d
Step-by-step explanation:
5(10+6) = 50x+30 or 30+50x.
Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
For A B and C, you just plug in the given number
A
B
C
And for D, you set the equation to 26 and solve for n
I had to use x instead of n, but for D n=7. :)
Answer:
-7
Step-by-step explanation:
