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3 years ago

15

Jack split 25 jellybeans between his brother and himself so that his brother has one more than twice the number Jack has. How ma

ny jellybeans does each have?

2 answers:

Firlakuza [10]3 years ago

8 0

Jack has 8
And his brother has 17

Aneli [31]3 years ago

5 0

Answer:

Jack has 8 and his brother has 17

Step-by-step explanation:

j = # jack has

b = # brother has

j + b = 25

b = 1 + 2j (brother has one more than twice the amount jack has)

j + 1 + 2j = 25

3j = 24

j = 8

b = 25-8 or 17

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3 years ago

Write three equivalent ratios for 10/12

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3 years ago

Read 2 more answers

What is the volume of a oblique cylinder with a height of 18 and a radius of 10

Mandarinka [93]

Answer:

$V=1,800\pi\ units^{3}$

Step-by-step explanation:

we know that

The volume of the cylinder is equal to

$V=\pi r^{2}h$

we have

$r=10\ units$

$h=18\ units$

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$V=\pi (10)^{2}(18)$

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4 years ago

Andrew says that 10x + 6 and 5x + 11 are equivalent because they both equal 16 when x= 1. Is Andre correct in saying they're equ

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Step-by-step explanation:

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7 0

3 years ago

The four-member math team at Pecanridge Middle School is chosen from the math club, which has three girls and five boys. How man

cestrela7 [59]

Answer:

$Total\ Selection = 30\ ways$

Step-by-step explanation:

Given

Girls = 3

Boys = 5

Required

How many ways can 2 boys and girls be chosen?

The keyword in the question is chosen;

This implies combination and will be calculated as thus;

$Selection =\ ^nC_r = \frac{n!}{(n-r)!r!}$

For Boys;

n = 5 and r = 2

$Selection =\ ^5C_2$

$Selection = \frac{5!}{(5-2)!2!}$

$Selection = \frac{5!}{3!2!}$

$Selection = \frac{5 * 4 * 3!}{3!*2 * 1}$

$Selection = \frac{20}{2}$

$Selection = 10$

For Girls;

n = 3 and r = 2

$Selection =\ ^3C_2$

$Selection = \frac{3!}{(3-2)!2!}$

$Selection = \frac{3!}{1!2!}$

$Selection = \frac{3 * 2!}{1 *2!}$

$Selection = \frac{3}{1}$

$Selection = 3$

Total Selection is calculated as thus;

$Total\ Selection = Boys\ Selection * Girls\ Selection$

$Total\ Selection = 10 * 3$

$Total\ Selection = 30\ ways$

5 0

4 years ago