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3 years ago

14

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

2 answers:

solong [7]3 years ago

8 0

1) -4.7
4) -1.7
10) 5.7
I’m sorry if I’m wrong

lina2011 [118]3 years ago

7 0

Answer is in the photo. I can only upload it to a file hosting service. link below!

tinyurl.com/wpazsebu

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What is the answer to the question?

Andreyy89

Answer:

17

Step-by-step explanation:

We have two congruent triangles here. Thus, b must be 17.

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3 years ago

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Solve: -15 = -2.7 + t

AVprozaik [17]

-15 = -2.7 + t

add 2.7 to each side

-15+2.7 = -2.7+2.7 +t

-12.3 = t

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3 years ago

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In ten minutes a heart can beat 700 times. At this rate in how many minutes will a heart beat 140 times? At what rate can a hear

kifflom [539]

About an minute and a half hope this helps

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4 years ago

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X= r-h/y<br> solve for h and r

malfutka [58]

X = r - h/y ; Solve for h & r

Let's first solve for h :)

Add h/y to both sides.

h/y + x = r

So, r = h/y + x

Now, let's solve for h.

x = r-h/y

Subtract r from both sides.

-r + x = -h/y

Multiply both sides by y.

y(-r + x) = y(-h/y)

Simplify.

-ry + xy = -h

Divide both sides by -1.

ry - xy = h

So, h = ry - xy

~Hope I helped!~

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3 years ago

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In circle C, what is mFH?<br><br> 31°<br> 48°<br> 112°<br> 121°

natta225 [31]

we know that

The measurement of the external angle is the semi-difference of the arcs it comprises.

so

Step $1$

<u>Find the measure of the arc AJ</u>

m∠BDE= $\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ BE]$

in this problem we have

m∠BDE= $37\°$

$measure\ arc\ BE=38\°$

substitute in the formula

$37\°$ = $\frac{1}{2} *[measure\ arc\ AJ-38\°]$

$74\°$ = $[measure\ arc\ AJ-38\°]$

$measure\ arc\ AJ=74\°+38\°=112\°$

Step $2$

<u>Find the measure of the arc FH</u>

m∠FGH= $\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ FH]$

in this problem we have

m∠FGH= $32\°$

$measure\ arc\ AJ=112\°$

substitute in the formula

$32\°$ = $\frac{1}{2} *[112\°-measure\ arc\ FH]$

$64\°$ = $[112\°-measure\ arc\ FH]$

$measure\ arc\ FH=112\°-64\°=48\°$

therefore

<u>the answer is</u>

the measure of the arc FH is $48\°$

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4 years ago

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