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3 years ago

Hi, can someone help me with this question?

Mathematics

2 answers:

Shalnov [3]3 years ago

6 0

Answer:

Soln

At first find the total area of figure then decrease the area with shaded region.

You can get answers.

inna [77]3 years ago

5 0

Split up the shape so first work out the top rectangle 9 x 2= 18
then the other rectangle 6x2 =12
18 +12 = 30m ^2
hope this helps

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a cooler contains 50 bottles; 30 bottles of water, which 8 are lemon flavored and 20 bottles of tea, of which 5 are lemon flavor

xenn [34]

Answer:

The required probability is $\dfrac{13}{50}$

Step-by-step explanation:

Total number of bottles = 50

Total number of water bottles = 30

Total number of lemon flavored water bottles = 8

Total number of tea bottles = 20

Total number of lemon flavored tea bottles = 5

Probability of selecting a lemon flavored water bottle = Probability of selecting a water bottle $\times$ Probability of selecting a lemon bottle out of water bottles.

Probability of selecting a lemon flavored tea bottle = Probability of selecting a tea bottle $\times$ Probability of selecting a lemon bottle out of tea bottles.

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Probability of selecting a water bottle:

$\dfrac{30}{50} = \dfrac{3}{5}$

Probability of selecting a lemon flavored bottle from water bottle:

$\dfrac{8}{30}$

Probability of selecting a lemon flavored water bottle = P(A)

$\dfrac{3}{5} \times \dfrac{8}{30} = \dfrac{4}{25}$

Probability of selecting a tea bottle:

$\dfrac{20}{50} = \dfrac{2}{5}$

Probability of selecting a lemon flavored bottle from tea bottle:

$\dfrac{5}{20} = \dfrac{1}{4}$

Probability of selecting a lemon flavored tea bottle = P(B)

$\dfrac{2}{5} \times \dfrac{1}{4} = \dfrac{1}{10}$

The required probability is:

P(A) + P(B):

$\dfrac{4}{25} + \dfrac{1}{10}\\\Rightarrow \dfrac{8+5}{50}\\\Rightarrow \dfrac{13}{50}$

8 0

3 years ago

A u.s. customs inspector decides to inspect 3 out of 16 shipments for contraband. find the probability that 2 out of the 3 shipm

xz_007 [3.2K]

There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.

There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%

_____
C(n,k) = n!/(k!(n-k)!)

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3 years ago

Two towers make up the Vertical Forest. One is 76 meters tall, and the other is 111 meters tall. How many feet taller is the hig

prisoha [69]

Answer: 114.8

Step-by-step explanation: first multiply 76 times 3.28 (249.28) then multiply 11 by 3.28 (364.08) and subtract to get your awnser

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2 years ago

A plane is flying from Albuquerque new Mexico to Austin Texas so far it has flown 161 miles or 23% of the total distance of the

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Step-by-step explanation: