Answer:
arithmetric
Step-by-step explanation:
the difference is so simple
Answer:
The speed in of the plane is 115.47 m/sec
Step-by-step explanation:
Given:
Height at which the plane is flying = 6000 m
Angle of elevation at the radar base = 30 Degrees
Angle of elevation at the radar base after one minute = 60 Degrees
To Find:
The Speed of the plane in meter per second = ?
Solution:
Let us use the tangent of the angle to find the distance (d) to a point directly below plane:
<u>when the angle is 30 degrees</u>



d1 = 10392.3 meters
<u>when the angle is 60 degrees</u>



d2 = 3464.1 meters
<u>distance travelled by aircraft in 1 min is </u>
=>d1 - d2
=>0392.3 - 3464.1
= 6928.2 m/min
<u>Now converting to m/sec</u>
=>
=>115.47 m/sec
I think it’s 45 but I may be wrong
He will have 20 smaller pieces of cheese.
To get the quotient you must divide 5 by 1/4. Since 1/4 is a fraction, turning it into a decimal would be .25.
5

In this item, we are to determine the value of x first and substitute the computed value to determine the lengths of QR and QS. Since we are given that two segments are perpendicular bisector of the isosceles triangle then, their lengths should also be equal.
QR = QS
Substituting with the given equation for each.
x/2 + 2 = x - 10
Multiply both sides of the equation by 2,
x + 4 = 2x - 20
Transpose all terms with variables to one side of the equation and the constants to the other.
x - 2x = -20 - 4
-x = -24
x = 24
QR: x/2 + 2 = 24/2 + 2 = 14
QS: x - 10 = 24 - 10 = 14
<em>ANSWER: QR = QS = 14</em>