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Lemur [1.5K]
3 years ago
11

Plz help if u can 20 pt please just don't take the points..

Mathematics
1 answer:
sergey [27]3 years ago
5 0

Answer:

b. 28x + 8y +2

Step-by-step explanation:

you need to distribute the -2 to all the numbers inside parentheses and then combine like terms.

-2*3x= -6x

-2*12y= -24y

-2*-5= 10 (remember neg times neg = pos)

-2*17= 34x

-2*-16y=32y

-2*4= -8

Now combine like terms

34x-6x= 28x

32y-24y=8y

10-8=2

Write the expression:  28x + 8y +2

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JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the<br><br> rhombus.
anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

JL = 48

KM = 20

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

P = 2\sqrt{(JL)^2 + (KM)^2}

Substitute values for JL and KM

P = 2\sqrt{48^2 + 20^2}

P = 2\sqrt{2304 +400}

P = 2\sqrt{2704}

P = 2 * 52

P = 104

<em>Hence, the perimeter is 104 units</em>

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