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riadik2000 [5.3K]
3 years ago
9

Work out m and c for the line:y=3x-2

Mathematics
1 answer:
Nikolay [14]3 years ago
7 0
Y = mx + c
m = gradient
c = y-intercept

Therefore, m=3 and c= -2
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Sedaia [141]
\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
&&  y={{ k }}x
\end{array}\\ \quad \\


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\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
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\end{array}


now, we know that V varies directly to T and inversely to P simultaneously
thus\bf V=T\cdot \cfrac{k}{P}

so     \bf V=T\cdot \cfrac{k}{P}\qquad 
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P=8
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\\\\\\
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MatroZZZ [7]

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To prove

As given

a∥e , m∥n , and m∠2 = 112°.

As  m∥n

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a∥e and m is transversal .

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Therefore

∠6 = 112°

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