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Art [367]
2 years ago
6

Whats 3a+a+5b-2b using the indicated operations​

Mathematics
2 answers:
Pepsi [2]2 years ago
6 0

Answer:

4a + 3b

Step-by-step explanation:

3a + a + 5b - 2b

3a + s = 4a

5b - 2b = 3b

<em><u>4a + 3b</u></em>

Westkost [7]2 years ago
5 0

Answer:

sorry sorry sorry sorry sorry

Step-by-step explanation:

no hablo inglés sorry

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Leah is building a slide for her kids. if the latter is 7 feet tall and she wants the bottom of the slide to be 4 feet from the
nadezda [96]

The line needs to be 8.06 m long

Explanation

Given that the ladder is 7 feet tall and the bottom of the slide should be 4 m away from the ladder.

The ladder,slide and the ground connecting them makes the sides of a right angled triangle with ladder as the height and ground as the base.

base=4m

height=7m

hypotenuse can be determined using pythagoras law

b^{2} +h^{2} =H^{2} \\x^{2} 4^{2}+ 7^{2}= H^{2} \\16+49=H^{2} \\H=\sqrt{65} \\=8.06 m

4 0
3 years ago
Math: Recursive Formula
olga55 [171]

Answer:

-10+12=2;+2

Step-by-step explanation:

4 0
3 years ago
Find the uncertainty in a calculated average speed from the measurements of distance and time. Average speed depends on distance
zzz [600]

Answer:

\frac{\Delta v}{v}=0.426

Step-by-step explanation:

you have that the average sped is given by the following formula:

v(x,t)=\frac{x}{t}

The uncertainty formula for a division is given by:

\frac{\Delta v}{v}=\sqrt{(\frac{\Delta x}{x})^2+(\frac{\Delta t}{t})^2}        (1)

Δv: uncertainty in speed

Δx: uncertainty in the distance = 0.9m

Δt: uncertainty in time = 0.7s

x: distance = 8.1m

t: time = 1.7s

You replace the values of all parameters in the equation (1):

\frac{\Delta v}{v}=\sqrt{(\frac{0.9}{8.1})^2+(\frac{0.7}{1.7})^2}\\\\\frac{\Delta v}{v}=0.426

Hence, the relation between the uncertainty in the average velocity is 0.426

4 0
3 years ago
Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?
Phantasy [73]

Answer:

\cos (a-b)=\cos a \cos b+\sin a \sin b

Step-by-step explanation:

 Given : \cos (180^{\circ}-q)=-\cos q

We have to write which identity we will use to prove the given statement.

Consider \cos (180^{\circ}-q)=-\cos q

Take left hand side of given expression \cos (180^{\circ}-q)

We know

\cos (a-b)=\cos a \cos b+\sin a \sin b

Comparing , we get, a= 180° and b = q

Substitute , we get,

\cos (180^{\circ}-q)=\cos 180^{\circ}  \cos (q)+\sin q \sin 180^{\circ}

Also, we know \sin 180^{\circ}=0 and \cos 180^{\circ}=-1

Substitute, we get,

\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0

Simplify , we get,

\cos (180^{\circ}-q)=-\cos (q)

Hence, use difference identity to  prove the given result.

7 0
3 years ago
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What is the surface area of the sphere below?
dexar [7]

Answer:

A =4πr2

Step-by-step explanation:

8 0
3 years ago
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