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mash [69]
3 years ago
11

Find the slope of: (12,-2) and (4, -6).

Mathematics
1 answer:
Lisa [10]3 years ago
4 0

Answer:

Slope is 1/2

Step-by-step explanation:

Brainliest please!

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Which linear inequality is represented by the graph?
Serga [27]

Answer:

A. y ≤ 1/2x + 2

Step-by-step explanation:

Well look at the graph,

It is a solid line with it shaded down,

meaning it is y ≤,

So we can cross out B. and D.

So the y intercept is 2, we know this because the y intercept is the point on the line that touches the y axis.

now the slope can be found by seeing how far away each points are from each other,

Hence, the answer is A. y ≤ 1/2x + 2

7 0
4 years ago
The sum of three certain consecutive numbers is 240. Find the three numbers. [Hint: Let x stand for the smallest number. Since t
Verdich [7]
The numbers are 79, 80, and 81.

79+80+81=240.
8 0
3 years ago
Mrs. Thaxton saved $700.00 to take her four grandchildren shopping. Her grandchildren are between the ages of 5 and 11. If Mrs.
anyanavicka [17]

Answer:

240

Step-by-step explanation:

115x4=460

700-460=240

8 0
3 years ago
Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.50 and P(B) = 0.20. (
True [87]

Answer:

a) 0

b) 0

c)No

d) Mutually exclusive event are not independent and when events are independent they cannot be mutually exclusive.

Step-by-step explanation:

From the question,

P(A) = 0.50

P(B) = 0.20.

a) Event A and event B cannot take place at the same time which means they are mutually exclusive, and whenever an event is not possible to take place, then the probability is Zero. Therefore,

P(A ∩ B)= 0

b) CHECK THE ATTACHMENT BELOW

c)No, the reason been that when event are mutually exclusive therefore, they cannot take place at the same time. Because when one event takes place here the other will not take place.

d) Mutually exclusive event are not independent and when events are independent they cannot be mutually exclusive.

6 0
3 years ago
Can anyone help me with these two problems?
Veseljchak [2.6K]

Show

\dfrac{\sin ^2 x + \sin x \cos x}{\cos x - 2 \cos^3 x} = \dfrac{\tan x}{\sin x - \cos x}

I don't like this computer aided instruction holding my hand.  I'll ignore that at first so I can compare my solution to the one being taught.

We can see how a tan factors out; let's see what's left.

\dfrac{\sin ^2 x + \sin x \cos x}{\cos x - 2 \cos^3 x}

=\dfrac{\sin x}{\cos x} \cdot \dfrac{ \sin x + \cos x}{1 - 2 \cos^2 x}

We need to factor out a sin x + cos x in the denominator so let's change one of the squared cosines to squared sine.

= \tan x \dfrac{ \sin x + \cos x}{1 - \cos^2 x - (1 - \sin ^2 x)}

= \tan x \dfrac{ \sin x + \cos x}{\sin^2 x - \cos^2 x}

= \tan x \dfrac{ \sin x + \cos x}{(\sin x + \cos x)(\sin x - \cos x)}

=\dfrac{\tan x}{\sin x - \cos x} \quad\checkmark

OK, now I can look at what they did.

First step ok, the box is 2 cos^2 x

Second step they changed the 1, box same as before: 2 cos^2 x

Third box matches our proof,  cos^2 x

Fourth box our last box didn't change:  cos^2 x

Fifth box: sin x + cos x

6 0
4 years ago
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