Answer:
The score that separates the lower 5% of the class from the rest of the class is 55.6.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

Find the score that separates the lower 5% of the class from the rest of the class.
This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.


The score that separates the lower 5% of the class from the rest of the class is 55.6.
The formula for the volume of a cone is V=(1/3)πr^2h.
To find r (radius) divide the diameter by 2, giving you 2.5 cm.
Plug in the numbers now !
V=(1/3)(3.14)(2.5^2)(9)
V=(1/3)(3.14)(6.25)(9)
V=(1/3)(176.625)
V=58.875
Therefore, the volume of the cone is about 59cm^3 :)
Answer:
I don't know. I need the whole question to answer.
Step-by-step explanation:
Sorry
6x+1 = 12x because the Z angles are the same
Solve this and you get:
1 = 12x - 6x => x = 1/6