To make it a fraction form answer, you multiply the whole number by the denominator and make the result the new numerator. The old numerator becomes the new denominator:
6 x 10
/5 = 60/ 5
Thus, the answer to 6 divided by 5/10 in fraction form is:
60
/5
To make the answer to 6 divided by 5/10 in decimal form, you simply divide the numerator by the denominator from the fraction answer above:
60 / 5 = 12
The answer is rounded to the nearest two decimal points if necessary.
60/5 can be simplified to 12/1.
12/1 is an improper fraction and should be written as 12.
The answer to your question is -34
we certainly could do so IF only IF the proportion of 12 and 2 are at the same ratio as 1½ and 1/3, namely if both yield the same fraction, let's see, and firstly converting the mixed fraction to improper.
![\bf \cfrac{12}{2}=\cfrac{~~1\frac{1}{2}~~}{\frac{1}{3}}\implies 6=\cfrac{~~\frac{1\cdot 2+1}{2}~~}{\frac{1}{3}}\implies 6=\cfrac{~~\frac{3}{2}~~}{\frac{1}{3}}\implies 6=\cfrac{3}{2}\cdot \cfrac{3}{1}\implies 6\ne \cfrac{9}{2}~~\bigotimes](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B12%7D%7B2%7D%3D%5Ccfrac%7B~~1%5Cfrac%7B1%7D%7B2%7D~~%7D%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%206%3D%5Ccfrac%7B~~%5Cfrac%7B1%5Ccdot%202%2B1%7D%7B2%7D~~%7D%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%206%3D%5Ccfrac%7B~~%5Cfrac%7B3%7D%7B2%7D~~%7D%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%206%3D%5Ccfrac%7B3%7D%7B2%7D%5Ccdot%20%5Ccfrac%7B3%7D%7B1%7D%5Cimplies%206%5Cne%20%5Ccfrac%7B9%7D%7B2%7D~~%5Cbigotimes)
A is the answer to this thingy thing
Given:
Dimensions of a block are w = 5 cm, l = 8 cm, h = 12 cm.
To find:
The length of the space diagonal of a block.
Solution:
Length of the diagonal is
![Diagonal=\sqrt{l^2+w^2+h^2}](https://tex.z-dn.net/?f=Diagonal%3D%5Csqrt%7Bl%5E2%2Bw%5E2%2Bh%5E2%7D)
Putting the given values, we get
![Diagonal=\sqrt{(8)^2+(5)^2+(12)^2}](https://tex.z-dn.net/?f=Diagonal%3D%5Csqrt%7B%288%29%5E2%2B%285%29%5E2%2B%2812%29%5E2%7D)
![Diagonal=\sqrt{64+25+144}](https://tex.z-dn.net/?f=Diagonal%3D%5Csqrt%7B64%2B25%2B144%7D)
![Diagonal=\sqrt{233}](https://tex.z-dn.net/?f=Diagonal%3D%5Csqrt%7B233%7D)
![Diagonal=15.2643375...](https://tex.z-dn.net/?f=Diagonal%3D15.2643375...)
Round to the nearest tenth.
![Diagonal\approx 15.3](https://tex.z-dn.net/?f=Diagonal%5Capprox%2015.3)
So, the length of the space diagonal of a block is 15.3 cm.
Therefore, the correct option is B.