Question

Emily's piggy bank contains twice as many dimes as nickels. It contains two more quarters than nickels. Emily calculates that if instead of the money she actually has, she has as many quarters as she has nickels, as many dimes as she has quarters, and as many nickels as she has dimes, then she would have $1,50 less than she actually has. How many nickels, how many dimes, and how many quarters are actually in Emily's piggy bank? Please no links

Answer 1

Answer:

24 nickles 48 dimes 26 quarters

Step-by-step explanation:

Answer 2

Answer:

Emily has 10 nickels, 20 dimes and 12 quarters in her piggy bank

Step-by-step explanation:

The number of dimes in Emily's piggy bank = 2 × The number of nickels

The number of quarters in it = 2 + The number of nickels

Whereby;

The number of quarters = The number nickels

The number of dimes = The number of quarters

The number of nickels = The number of dimes

The total amount = Current amount - $150

Let 'x' represent the number of dimes, let 'y' represent the number nickels, and let 'z' represent the number quarters in Emily's piggy bank, we have;

x = 2 × y

z = 2 + y

The total amount in the piggy bank is therefore;

Total = C = x×0.1  + y×0.05 + z×0.25 = 2·y×0.1 + y × 0.05 + (2 + y) × 0.25 = 0.5·y + 0.5

C = 0.5·y + 0.5

With the second condition, we have;

z = y

x = z

y = x

We get

x × 0.1 + y × 0.05 + z × 0.25 = y ×0.1 + y×0.05 + y×0.25 = 0.4·y = C - 1.5

∴ C = 0.4·y + 1.5

Which gives;

0.5·y + 0.5 = 0.4·y + 1.5

0.1·y = 1.5 - 0.5 = 1

y = 1/0.1 = 10

y = 10

Therefore;

x = 2×y = 2 × 10 = 20

z = 2 + y = 2 + 10 = 12

Therefore;

The number number of nickels in her piggy bank, y = 10

The number of dimes in her piggy bank, x = 20

The number of quarters in her piggy bank, z = 12