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2 years ago

What is 99 divided by x to the second power

Mathematics

2 answers:

Natalka [10]2 years ago

6 0

99/x^2 ^ means to the 2nd power

maw [93]2 years ago

6 0

99 because x= 1 and by the power of 2 is 99/x^2 which is basically dividing 99 by one

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Solve 8(m - 5 ) = 48

Art [367]

Answer

$1)8(m -5 ) = 48 \\ 8m - 40 = 48 \\ 8m = 48 + 40 \\ 8m = 88 \\ \frac{8m}{8} = \frac{88}{8} \\ m = 11$

$2)x + 7 = 13 \\ x = 13 - 7 \\ x = 6$

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2 years ago

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4 birlik + 9 binlik + 1 yüz binlik + 9 yüzlük ten oluşan sayı?

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Answer:

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Step-by-step explanation:

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6 0

2 years ago

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

2 years ago

A force of 50 pounds is exerted at an angle of 80 with the horizontal. What is its horizontal component?

Shalnov [3]

Answer:

Option A is the correct answer.

Explanation:

Any vector can be resolved in to two components. Horizontal component and vertical component.

Consider a vector F which is at angle θ⁰ to the horizontal, we can resolve this vector in to two.

Horizontal component = F cos θ

Vertical component = F sin θ

Here we have Force , F = 50 pounds

Angle with horizontal = 80°

Horizontal component = F cos θ = 50* cos 80 = 8.68 pounds

≅ 9 lb.

Option A is the correct answer.

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3 years ago

Please helpppp !!!!!!!!!!!! Will<br> Mark Brianliest !!!!!!!!!!!!!!!!!!!!

Alexxx [7]

Answer:

Step-by-step explanation:

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3 years ago