For rigt triangle with legs legnth a and b and hypotnuse legnth c
a^2+b^2=c^2
we are given
larger leg is 3 longer than smaller leg
hypotnuse is 6 longer than smaller
find smaller
ok so
first pick a smaller leg
lets say b is smaller
longer leg is 3 more than shorter leg
a is 3 more than b
a=3+b
and
hypontuse is 6 more than shorter
c=6+b
sub 3+b for a and 6+b for c in oroiginal equation'
a^2+b^2=c^2
(3+b)^2+b^2=(6+b)^2
9+6b+b^2+b^2=36+12b+b^2
2b^2+6b^2+9=b^2+12b+36
minus (b^2+12b+36) from both sides
b^2-6b-27=0
factor
(b-9)(b+3)=0
set equal to zero
b-9=0
b=9
b+3=0
b=-3
fasle, legnths cannot be negative
answer is shorter side=9 cm
Answer:
a₁ = 1
r = 3
Step-by-step explanation:
Since it’s a geometric series then
a₁ = 1 ( because 1 is the first term of the series)
3/1 = 9/3 = 27/9 = 81/27 = 3 then r=3.
Step-by-step explanation:
Answer:
Step-by-step explanation:
- 4 > - 3, correct as 4 is to the right of - 3
- - 3 > 4, incorrect as - 3 is to the left of 4
- - 2 < - 3, incorrect as - 3 is to the left of - 2
- - 3 < - 6, incorrect as - 6 is to the left of - 3
