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3 years ago

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A line segment with both its endpoints on the circumference and which does not pass through the centre of the circle. is what di

amater, arc, tangent ,sector, segment, chird , circumference ,centre ir radius

1 answer:

poizon [28]3 years ago

3 0

Answer:

Hi how are you doing today Jasmine

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What is the answer??

levacccp [35]

Answer:

76 unit^2

Step-by-step explanation:

Total area: (0.5 * base * height) +( length * breadth ) + (0.5 * base * height)

= (0.5 * 8 * 2) + ( 7*8) +( 0.5 * 8 * 3) = 8 + 56 + 12 = 76

7 0

2 years ago

What is the equation of the line in slope-intercept form? the line perpendicular to

valentinak56 [21]

Perpendicular has slope tha multiplies to -1
y=mx+b
m=slope
y=1/3x+b
1/3=slope
1/3 times what=-1?
-3 is answer

y=-3x+b
find b
given
(2,1)
(x,y)
x=2 and y=1 is a solution

1=-3(2)+b
1=-6+b
add 6
7=b

y=-3x+7

B is answer

3 0

3 years ago

How do I simplify this?

Aleksandr [31]

Answer:

whats to simplify

Step-by-step explanation:

actally

4 0

4 years ago

Express 60 as the product of its prime factors.

nasty-shy [4]

Answer:

2^2x3x5=60

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Applying properties of Exponents In Exercise, use the properties of exponents to simplify the expression.

eimsori [14]

Answer:

(a) $5^{8}$

(b) 3

(c) 27

(d) $\dfrac{1}{6}$

Step-by-step explanation:

We need simplify the given expressions.

(a)

Consider the given expression is

$(5^4)(25^2)$

$(5^4)((5^2)^2)$

Using the properties of exponents we get

$(5^4)(5^4)$ $[\because (a^m)^n=a^{mn}]$

$5^{4+4}$ $[\because a^ma^n=a^{m+n}]$

$5^{8}$

(b)

Consider the given expression is

$(9^{\frac{1}{3}})(3^{\frac{1}{3}})$

$((3^2)^{\frac{1}{3}})(3^{\frac{1}{3}})$

Using the properties of exponents we get

$(3^{\frac{2}{3}})(3^{\frac{1}{3}})$ $[\because (a^m)^n=a^{mn}]$

$3^{\frac{2}{3}+\frac{1}{3}}$ $[\because a^ma^n=a^{m+n}]$

$3^{1}$

$3$

(c)

Consider the given expression is

$(\dfrac{1}{3})^{-3}$

Using the properties of exponents we get

$(\dfrac{3}{1})^{3}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$3^{3}$

$27$

(d)

Consider the given expression is

$(6^4)(6^{-5})$

Using the properties of exponents we get

$6^{4+(-5)}$ $[\because a^ma^n=a^{m+n}]$

$6^{-1}$

$\dfrac{1}{6^{1}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{1}{6}$

6 0

3 years ago