Answer: a) 4.6798, and b) 19.8%.
Step-by-step explanation:
Since we have given that
P(n) = 
As we know the poisson process, we get that
So, for exactly one car would be
P(n=1) is given by
Hence, our required probability is 0.2599.
a. Approximate the number of these intervals in which exactly one car arrives
Number of these intervals in which exactly one car arrives is given by
We will find the traffic flow q such that
b. Estimate the percentage of time headways that will be 14 seconds or greater.
so, it becomes,
Hence, a) 4.6798, and b) 19.8%.
Answer:
m ≥ –6
Step-by-step explanation:
m+5 ≥ –1
subtract 5 from both sides
m ≥ -6
We can adjust the data by adding 4 to everything before we calculate the statistics. Or we can calculate the statistics on the given data and just add 4 to everything at the end. We'll get the same answer either way.
Let's sort the seven data points: 5 5 5 7 7 9 10
Those add up to 48 so the mean is 48/7 = 6.9
The one in the middle is 7 so the median = 7
The mode is the most common one, mode = 5
The range is the difference between max and min, so range = 10 - 5 = 5
In the second week we add four to everything. Since that adds four to the min and max, the range doesn't change.
Answer: mean=10.9, median=11, mode=9, range=5
The y int is where the line crosses the y axis...it is (0,1)...or just 1
1 minute, the number of minutes students stretch when they do not jog
