Answer:
yzx and tus
Step-by-step explanation:
Answer:
D) Acceleration is positive and increasing.
Step-by-step explanation:
In formulae, acceleration is defined as the rate of change of velocity per unit time; for example:
where Δ V is the variation of velocity and Δ T is the variation in time.
The graph depicts the velocity of a moving item as a function of time. As we can see ΔV is the increment on the y-axis, while ΔT is the increment on the x axis: therefore, the ratio ΔV/ΔT is the curve's slope. In fact, the slope of the curve in a velocity-time graph corresponds to the object's acceleration. In this graph, we can see that the slope of the curve is growing, which means that the acceleration is positive (since the slope is positive and the velocity is increasing) and increasing (because the slope is increasing).
Answer: 21
Step-by-step explanation: We can rewrite this problem as:
What is 60% of 35?
"Percent" or "%" means "out of 100" or "per 100", Therefore 60% can be written as 60/100
When dealing with percent's the word "of" means "times" or "to multiply".
Finally, lets call the number of members we are looking for "m".
Putting this altogether we can write this equation and solve for
m
while keeping the equation balanced: m=60/100*35
m=2100/100
m=21
Answer:
74
Step-by-step explanation:
The mean of any set of numbers is simply the sum of the numbers divided by however many numbers you have. Because of this you can write the following equation
Mean = (sum of numbers)/(number of numbers)
Let's say that the missing test score is called x:
Mean = 80 = (80 + 85 + 73 + 78 + 90 + x)/6
80(6) = 80 + 85 + 73 + 78 + 90 + x
480 = 80 + 85 + 73 + 78 + 90 + x
x = 480 - 80 - 85 - 73 - 78 - 90
x = 74
The solution would be like this
for this specific problem:
8479 = P * (1 + 0.09/2)^(2 * 6) <span>
8479 = P * (1 + 0.045)^12
8479 / (1.045)^12 = P
P = 4999.7599101968641899706115543368</span>
If the money was invested at 9%
interest compounded semiannually, the initial investment is $5000. I am hoping that this answer has
satisfied your query and it will be able to help you in your endeavor, and if
you would like, feel free to ask another question.