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3 years ago

WILL MARK BRAINLIEST Given: isoceles trapezoid BEAR, Find AQ

Mathematics

1 answer:

MAXImum [283]3 years ago

6 0

Answer:

beleive the anser is 12 try that

Step-by-step explanation:

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ASAP!!!

77julia77 [94]

The answer is D. This is because She already marked off 18.7 and the total amount is 29.

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=11%20%2B%20k%20%3D%20%20-%202" id="TexFormula1" title="11 + k = - 2" alt="11 + k = - 2" alig

Mekhanik [1.2K]

$11 + k = - 2 \\ = - 2 - 11 \\ = - 13$
so K is -13

4 0

3 years ago

Solve using quadratic formula for 2x^(2)-10x+5=0

sergij07 [2.7K]

Answer:

$x=\frac{5+\sqrt{15}}{2},\:x=\frac{5-\sqrt{15}}{2}$

Step-by-step explanation:

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=-10,\:c=5$

$x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:2\cdot \:5}}{2\cdot \:2}$

$\sqrt{\left(-10\right)^2-4\cdot \:2\cdot \:5}$

Apply exponent rule: (-a)^n=a^n, if n is even

$\left(-10\right)^2=10^2$

$=\sqrt{10^2-4\cdot \:2\cdot \:5}$

$\mathrm{Multiply\:the\:numbers:}\:4\cdot \:2\cdot \:5=40$

$=\sqrt{10^2-40}$

$10^2=100$

$=\sqrt{100-40}$

$\mathrm{Subtract\:the\:numbers:}\:100-40=60$

$=\sqrt{60}$

$60\:\mathrm{divides\:by}\:2\quad \:60=30\cdot \:2$

$=2\cdot \:30$

$30\:\mathrm{divides\:by}\:2\quad \:30=15\cdot \:2$

$=2\cdot \:2\cdot \:15$

$15\:\mathrm{divides\:by}\:3\quad \:15=5\cdot \:3$

$=2\cdot \:2\cdot \:3\cdot \:5$

$2,\:3,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}$

$=2\cdot \:2\cdot \:3\cdot \:5$

$=2^2\cdot \:3\cdot \:5$

$=\sqrt{2^2\cdot \:3\cdot \:5}$

Apply Radical Rule:

$=\sqrt{2^2}\sqrt{3\cdot \:5}$

Apply Radical Rule:

$\sqrt{2^2}=2$

$=2\sqrt{3\cdot \:5}$

$\mathrm{Refine}$

$=2\sqrt{15}$

$x_{1,\:2}=\frac{-\left(-10\right)\pm \:2\sqrt{15}}{2\cdot \:2}$

$\mathrm{Separate\:the\:solutions}$

$x_1=\frac{-\left(-10\right)+2\sqrt{15}}{2\cdot \:2},\:x_2=\frac{-\left(-10\right)-2\sqrt{15}}{2\cdot \:2}$

$\frac{-\left(-10\right)+2\sqrt{15}}{2\cdot \:2}$

Apply Rule -(-a)=a

$=\frac{10+2\sqrt{15}}{2\cdot \:2}$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2=4$

$=\frac{10+2\sqrt{15}}{4}$

$=\frac{2\left(5+\sqrt{15}\right)}{4}$

$\mathrm{Cancel\:the\:common\:factor:}\:2$

$=\frac{5+\sqrt{15}}{2}$

$\frac{-\left(-10\right)-2\sqrt{15}}{2\cdot \:2}$

$=\frac{10-2\sqrt{15}}{2\cdot \:2}$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2=4$

$=\frac{10-2\sqrt{15}}{4}$

$=\frac{2\left(5-\sqrt{15}\right)}{4}$

$\mathrm{Cancel\:the\:common\:factor:}\:2$

$=\frac{5-\sqrt{15}}{2}$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{5+\sqrt{15}}{2},\:x=\frac{5-\sqrt{15}}{2}$

8 0

3 years ago

- 2 root 2 + root 2 ?

KonstantinChe [14]

The answer is -root 2

Mark as brainliest plz.

8 0

3 years ago

14% of the town's population is over the age of 65. If there are 320 residents over the age of 65, approximately what is the tow

marshall27 [118]

Answer & Step-by-step explanation:

So if 14% are over 65, and 320 residents are over 65, then we can say that 14% of the town is 320. Then, we can divide by 14 to find 1%, which is 22.857142857 Now we can multiply this by 100 to get 2285.7142857, which is the answer. To double check, you'd just find 14% of 2285.7142857 (multiply by 0.14) which is equal to 320. Because you can't have fractions of people, however, you'd have to round the answer up to 2286 people.

If that is too difficult to understand them hope this is easier

14% of the towns population is 320. Let P denote the towns population.

14/100 * P =320

14P/100 = 320

14P = 32000

divide both sides by 14

P = 2285.71

the towns population is 2286

Hope this helps!

5 0

3 years ago