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MariettaO [177]
3 years ago
7

Tell whether the relation is a function. {(-5, -3), (-1, 3), (4, 3), (8, 8)}

Mathematics
1 answer:
VladimirAG [237]3 years ago
8 0

Given:

The relation is {(-5, -3), (-1, 3), (4,3), (8, 8)}.

To find:

Whether the given relation is a function or not.

Solution:

A relation is called a function, if there exist a unique output for each input.

We have, a relation given as

{(-5, -3), (-1, 3), (4,3), (8, 8)}

Here, all x-values are different. So, each x-value has a unique y-value.

Thus, there exist a unique output for each input.

Therefore, the given relation is a function.

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Can somebody help me with this it a little hard
raketka [301]

24 3-pound bags(72 pounds) and 10 5-pound bags(50 pounds). 72+50 = 122 pounds, 24+10 bags = 34 bags.

7 0
3 years ago
I really need help with this ?
quester [9]

Answer:

Answer=44

Step-by-step explanation:

Rectangle: 6x4=24.

Triangle: 4x4=16, and 16/2=8.

Semicircle: Pi x radius squared, so pi x 2 squared is 16.something, and since it's a semicircle, we divide by 2, so it's 8 again.

Overall: 24+8+8=44 cm squared.

3 0
3 years ago
Find the midpoint of the segment with the given endpoints.
Ksju [112]

The mid-point for given endpoints is (4,3)

Step-by-step explanation:

a mid-point is the point on a line segment that divides it into two equal portions.

If (x1,y1) and (x2,y2) are the coordinates of vertices of a line segment, then mid-point is given by:

M = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

given

(x1,y1) = (9,9)

(x2,y2) = (-1,-3)

M = (\frac{9-1}{2}, \frac{9-3}{2})\\\\=(\frac{8}{2}, \frac{6}{2})\\\\=(4,3)

The mid-point for given endpoints is (4,3)

Keywords: Coordinate Geometry, Mid-point

Learn more about coordinate geometry at:

  • brainly.com/question/4639731
  • brainly.com/question/4655616

#LearnwithBrainly

5 0
3 years ago
Measuring the height of a tree is usually more difficult than measuring the diameter of the tree. Therefore, many researchers us
LenKa [72]

Answer:

(B) (0.396, 1.712)

Step-by-step explanation:

From the information given;

Confidence Interval = 0.95

Significance Level = 1 - 0.95 = 0.05

The confidence interval for regression coefficient beta (whereby in this case it is the coefficient of the diameter) is expressed by:

= ( Beta ^- \ t_{n-2}, \alpha/2 ( S.E \ of \ \^ \ \ ), Beta^+ \ t_{n-2}, \alpha/2 ( S.E \ of \ \^ \ \ ))

From the regression coefficient, the estimated value of beta^  = 1.054

= (1.054 - t_{29,0.025} *(0.322), 1.054 + t_{29,0.025}*(0.322))

t_{229,0.025} = 2.0452\\\\ = \mathbf{(0.396, 1.712)}

8 0
3 years ago
7. What is the equation of the line that passes through (-1, -4) and (0,5)?
Serga [27]

Answer:

A)y=9x+5

Step-by-step explanation:

If x=-1, y=-4,

  y=9*-1+5=(-9)+5=-4

If x=0, y=5,

  y=9*0+5=5

3 0
3 years ago
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