Answer: yes please and thank you in advance :)
Answer:
I would multiply the first equation by −4 and the second by 3 and add together the two equatins (in columns): ... Step 2. Prepare the equations. Multiply every term in each equation by a ... Subtract Equation (4) from Equation (3). ... How do you solve the system 5x−10y=15 and 3x−2y=3 by multiplication?
Answer:
Step-by-step explanation:
Y)
= 3
*multiply both sides by 8 - cancels out 8 in denominator*
x + 4 = 24
*subtract 4 from both sides*
x = 20
E)
= 1
*multiply both sides by 2 - cancels out 2 in denominator*
x - 5 = 2
*add 5 on both sides*
x = 7
N)
= 2
* multiply both sides by 4 - cancels out 4 in denominator*
x + 2 = 8
*subtract 2 from both sides*
x = 6
$38.95-$29.95= $9
$9= 900¢
900¢/3¢= 300
Ans: She used 300 minutes.
Answer:I go with A,C,E
Step-by-step explanation:
hope this help