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Softa [21]
3 years ago
5

PLZZ HELP !!!.... Based on this information, which of the organisms can produce offspring that

Biology
1 answer:
fenix001 [56]3 years ago
4 0
The answer is the last one: amoebas, yeasts, hydras, and ferns
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Bob, a nutritionist who works for the university medical center, has been asked to prepare special diets for two patients, susan
abruzzese [7]

Answer and Explanation:

Possibly, you forgot to attach the table with the contents of each food. Therefore, I calculated the task with similar values.

1. <em>Assume you have Food A, B, and C. Each has certain amount of Calcium, Iron, and Vit C. </em>

<em>             </em>Let's designate: Calcium <em>→ X oz , Iron → Y oz, vit C → Z oz</em>

2. <em>Assume you have following amount of</em><em> Calcium</em><em> in each food: </em>

  • Food A = 30 mg/oz
  • Food B = 25 mg/oz
  • Food C = 20 mg/oz

3. <em>Assume you have following amount of</em><em> Iron </em><em>in each food: </em>

  • Food A = 1 mg/oz
  • Food B = 1 mg/oz
  • Food C = 2 mg/oz

4. <em>Assume you have following amount of</em><em> vit C </em><em>in each food: </em>

  • Food A = 2 mg/oz
  • Food B = 5 mg/oz
  • Food C = 4 mg/oz

<u>Calculations:</u>

→ You have 3 different food and each has Calcium in it. You need exactly 320mg of Calcium per day. Therefore, each food would comprise certain proportion of daily Calcium intake. We can come up with equation: 30X+25Y+20Z = 390 mg

  • Similarly, for iron and vitamin C, the next equations could be used:

        X+Y+2Z=17 - Iron

        2X+5Y+4Z=42 - Vit C

→ Now you have a system of equations:

30X+25Y+20Z = 390 <em>(1) </em>

X+Y+2Z=17 <em>(2)</em>

2X+5Y+4Z=42 <em>(3)</em>

→ Look for similarities! <em>(1) and (3) </em>seem to be similar. We can multiply the <em>(3) </em>by -5 to obtain: -10X-25Y-20Z=-210. We add the <em>(1)</em> and modified <em>(3)</em> equations.

30X+25Y+20Z = 390

-10X-25Y-20Z=-210

__________________

20X+0+0=180

20X=180

<em><u>→ X=9 (oz of Calcium)</u></em>

<em><u></u></em>

→ Now, we can put<em> x=9 </em>into equations above to ease our job:

270+25Y+20Z=390 → 25Y+20Z=390-270=120

9+Y+Z=17 → Y+2Z=17-9=8

18+5Y+4Z=42 → 5Y+4Z=42-18=24

→ Similarly, we can use Eq-s <em>(2) and (3). </em>We can multiply the <em>(2) </em>by -5 to obtain: -5Y-10Z=-40. We add the <em>(3)</em> and modified <em>(2)</em> equations.

-5Y-10Z=-40

5Y+4Z=24

__________________

-6Z=-24

Z=4

<em><u>→ Z=4 (oz of vit C)</u></em>

<em><u></u></em>

→ Now, we can take X+Y+Z=17 <em>(2) </em>and just put in known values(<em>X=9 and Z=4</em>) to obtain Y:

9+Y+4=17

<u>→ Y=17-9-4=4 (oz of Iron)</u>

<u></u>

That's all! So, if you have table values, you can just re-write the equations and doing it stepwise, as it is shown here, you can manage to calculate every value you need :)

3 0
3 years ago
15. When there is light, plants do which of the following biological<br> processes?<br> *
zhuklara [117]

Answer: Plants do both photosynthesis and cellular respiration.

Explanation:

All cells do cellular respiration even without light.

Honestly, photosynthesis alone would be right since the teacher didnt  state the questions correctly. But you should choose both cause in the light it does both.

6 0
3 years ago
Which type of change would be more likely to have se­vere consequences—substitution or deletion? Why?
ludmilkaskok [199]

While both will equate changes in a genetic chain, deletion would have more severe consequences.  A substitution mutation usually only causes minor disorders and diseases, like sickle cell anemia.  Whereas deletion causes much more serious diseases, like cystic fibrosis, and turner syndrome which is  where a female is born with only one X chromosome.  

5 0
3 years ago
Describe the role of chiasmata in chromosome segregation during meiosis.
Aleksandr [31]

Explanation:

The phase of Prophase I of meiosis is very long and divided into 5 subphases: Leptotene, Zygote, Pachytene, Diplotene, and Diakinesis. During a phase of the Diplotene, the degree of condensation is high, which allows individualizing the sister- chromatids that remain attached by the cohesins. The synaptonemal complex disintegrates, and from the centromeres begins a repulsion between homologous chromosomes, which remain associated only with the places where they occur as permutations.

These sites are called chiasmas (Greek, crossed) because they show the crossover of homologous chromatids. Chiasmas represent the cytological finding of the occurrence of permutation. The presence of at least one bivalent chiasm is essential to ensure the correct segregation of the homologous chromosomes in anaphase I.

6 0
3 years ago
Which of the following is responsible of holding DNA ​
jeka57 [31]

Answer:

Hydrogen bonds.

Explanation:

The DNA double helix is held together by two main forces: hydrogen bonds between complementary base pairs inside the helix and the Van der Waals base-stacking interaction.

4 0
3 years ago
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