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stealth61 [152]
2 years ago
12

Whats y'alls answer streak, mine is 10. Highest gets brainiest! (not how many questions you have answered.

Mathematics
2 answers:
Nataliya [291]2 years ago
8 0

Answer:

I just started

Step-by-step explanation:

Airida [17]2 years ago
8 0

Answer:

mine was 37 but i broke it 3 days ago :(

so now its 3

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You have at most $75 to spend on books and music. You want to spend less than $20 on music and no more than $60 on books. Which
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60$ on books with 15$ for music, subtraction

Step-by-step explanation:

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3 years ago
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If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)] 2.<br><br> 1<br> 2<br> 9
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(2)2+1=5

3(1)+1=4 is your answer


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3 years ago
Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

  • \sin{\theta} < \cos{\theta} if 0^{\circ} < \theta;
  • \sin{\theta} > \cos{\theta} if 45^{\circ} < \theta;
  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

4 0
3 years ago
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PLEASE HELP WILL GET BRAINIEST
NeX [460]
You have a lot of questions here, I can help you with a few of them.

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Here are the answers for the first three:


1) 8x^3+2x^2-3x+9&#10;

2)  4w^2 + 14w + 17

3)  -3x^3+9x^2 +3x
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