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zaharov [31]
3 years ago
10

In triangle $XYZ,$ $\angle Y = 45^\circ$ and $\angle Z = 60^\circ.$ If $XZ = 4,$ then what is $XY$?

Mathematics
2 answers:
tino4ka555 [31]3 years ago
7 0

Answer:

XY = 4.9

Step-by-step explanation:

GalinKa [24]3 years ago
5 0

Answer:

XY = 4.9

Step-by-step explanation:

\angle Y = 45^\circ

\angle Z = 60^\circ

XZ = 4

Required

Determine the length of XY?

This question is supported with the attachment.

To solve for the length of XY, we make use of the sine law which states:

\frac{sin\ A}{a} = \frac{sin\ B}{b} = \frac{sin\ C}{c}

In this case:

\frac{sin\ \angle Y}{XZ} = \frac{sin\ \angle Z}{XY} = \frac{sin\ X}{YZ}

Substitute in, the following values:

\angle Y = 45^\circ

\angle Z = 60^\circ

XZ = 4

The expression becomes:

\frac{sin\ 45}{4} = \frac{sin\ 60}{XY}

Cross multiply

XY * \sin\ 45 = 4 * \sin\ 60

Make XY the subject

\frac{XY * \sin\ 45}{\sin\ 45} = \frac{4 * \sin\ 60}{\sin\ 45}

XY = \frac{4 * \sin\ 60}{\sin\ 45}

XY = \frac{4 * 0.8660}{0.7071}

XY = \frac{3.4640}{0.7071}

XY = 4.89888276057

XY = 4.9 --- approximated

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