Which is a solution to the inequality y > 2 + 9x? Select all that apply.

In 1985, there was 285 cell phones subscribers in the small town of centerville.After 1985, the number of subscribers increased

wolverine [178]

First we write a function that suits the problem.
We have then:
y = 285 * (1.75) ^ x
Then, we see how many years there are in the requested period
x = 1994-1985 = 9
We evaluate the function for x = 9
y = 285 * (1.75) ^ 9
y = 43871.98637
Round nearest whole number
y = 43872
Answer:
there were 43872 cell phones subscribers in centerville in 1994

4 0

3 years ago

ASAP! I NEED THIS DONE AS QUICKLY AS POSSIBLE WITH WORKING OUT

Elza [17]

Answer:

See explanation.

Step-by-step explanation:

Let us first analyze some principle theory. By definition we know that the velocity ( $v$ ) is a function of a distance ( $d$ ) covered in some time ( $t$ ), whilst acceleration ( $a$ ) is the velocity achieved in some time. These can also been expressed as:

$v = \frac{d}{t}\\$ and $a=\frac{v}{t}$

We also know that both velocity and acceleration are vectors (therefore they are characterized by both a magnitude and a direction). Finally we know that given a position vector we can find the velocity and the acceleration, by differentiating the vector with respect to time, once and twice, respectively.

Let us now solve our problem. Here we are givine the Position vector of a particle P (in two dimensional space of $i-j$ ) as:

$r=(3t^3-t+3)i+(2t^2+2t-1)j$ Eqn.(1)

Let us solve.

Part (a) Velocity: we need to differentiate Eqn.(1) with respect to time as:

$v(t)=\frac{dr}{dt}\\\\ v(t)=[(3)3t^2-1]i+[(2)2t+2]j\\\\v(t)=(9t^2-1)i+(4t+2)j$ Eqn.(2)

Part (b) Acceleration: we need to differentiate Eqn.(2) with respect to time as:

$a(t)=\frac{dv}{dt}\\ \\a(t)=[(2)9t]i+4j\\\\a(t)=(18t)i+4j$

Thus the expressions for the velocity and the acceleration of particle P in terms of t are

$v(t)=(9t^2-1)i+(4t+2)j$ and $a(t)=(18t)i+4j$

6 0

4 years ago

Find the measure of CDE. The measure of CDE equals a certain # of degrees.

vredina [299]

2x-13+3x-8+2x-3+2x-7+3x-1+2x+11+2x+9= (7-2)×180

16x-12=(7-2)×180

(7-2)×180 Work this out on a calculator

And then that answer=16x-12

Then you solve by adding 12 both sides and dividing by 16 both sides to get what x is.

7 0

3 years ago

The factory quality control department discovers that the conditional probability of making a manufacturing mistake in its preci

Anni [7]

Answer:

The probability that a defective ball bearing was manufactured on a Friday = 0.375

Step-by-step explanation:

Let the event of making a mistake = M

The event of making a precision ball bearing production on Monday = Mo

The event of making a precision ball bearing production on Tuesday = T

The event of making a precision ball bearing production on Wednesday = W

The event of making a precision ball bearing production on Thursday = Th

The event of making a precision ball bearing production on Friday = F

the conditional probability of making a manufacturing mistake in its precision ball bearing production is 4% on Tuesday, P(M|T) = 4% = 0.04

4% on Wednesday, P(M|W) = 0.04

4% on Thursday, P(M|Th) = 0.04

8% on Monday, P(M|Mo) = 0.08

and 12% on Friday = P(M|F) = 0.12

The Company manufactures an equal amount of ball bearings (20 %) on each weekday, Hence, the probability that a random precision ball bearing was made on a particular day of the week, is mostly the same for all the five working days.

P(Mo) = 0.20

P(T) = 0.20

P(W) = 0.20

P(Th) = 0.20

P(F) 0.20

The probability that a defective ball bearing was manufactured on a Friday = P(F|M)

P(F|M) = P(F n M) ÷ P(M)

P(F n M) = P(M n F)

P(M) = P(Mo n M) + P(T n M) + P(W n M) + P(Th n M) + P(F n M)

We can obtain each of these probabilities by using the expression for conditional probability.

P(Mo n M) = P(M|Mo) × P(Mo) = 0.08 × 0.20 = 0.016

P(T n M) = P(M|T) × P(T) = 0.04 × 0.20 = 0.008

P(W n M) = P(M|W) × P(W) = 0.04 × 0.20 = 0.008

P(Th n M) = P(M|Th) × P(Th) = 0.04 × 0.20 = 0.008

P(F n M) = P(M|F) × P(F) = 0.12 × 0.20 = 0.024

P(M) = P(Mo n M) + P(T n M) + P(W n M) + P(Th n M) + P(F n M)

P(M) = 0.016 + 0.008 + 0.008 + 0 008 + 0.024 = 0.064

P(F|M) = P(F n M) ÷ P(M)

P(F n M) = P(M n F) = 0.024

P(M) = 0.064

P(F|M) = P(F n M) ÷ P(M) = (0.024/0.064) = 0.375

Hope this Helps!

4 0

3 years ago

The cost of renting a car is $45/wk plus $0.15/mi traveled during that week. An equation to represent the cost would be

Tpy6a [65]

Y= 45 + 0.15(60)
Y= 45 + 9
Y= 45

5 0

4 years ago