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-Dominant- [34]
3 years ago
10

WILL MARK BRAINLIEST WILL REPORT IF U GIVE ME A LINK TO UKNOWN THING

Mathematics
1 answer:
meriva3 years ago
5 0

Answer:

I think the answer will be x⩽4

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If b/a=c/b=d/c=2/3, find the value of a:b:c:d
leva [86]

Answer:

the ratio would be 6.75:4.5:3:2

Step-by-step explanation:

replace d and c with

d=2 and c=3

Then using proportion multiplication, you will find that b is 4.5

now replace all b with 4.5.

Then again using proportion multiplication, you will get a is 6.75.

Plug in a, b, c, d in the ratio and you get 6.75:4.5:3:2

5 0
2 years ago
PLSSS HELP ILL GIVE BRAINLIEST!!!,!!!
Alexus [3.1K]

rewrite -1 1/3 as a decimal: -1.5


-2.1 - x = -1.5

Subtract -2.1 From both sides:

X = -1.5 - -2.1 = -1.5 + 2.1

X = 0.6


Answer: B. 0.6

6 0
2 years ago
Read 2 more answers
8х + 5у = -7<br> — 7х + бу = — 4
Levart [38]

Answer: x = -0.2651 and y = -0.9759

Step-by-step explanation:

Solution by substitution method

8x+5y= -7

-7x+6y= -4 = 7x-6y=4

Suppose,

8x+5y=-7→(1)

7x-6y=4→(2)

Taking equation (1), we have

8x+5y= -7

⇒8x= -5y -7

⇒x= -5y-7 / 8 →(3)

Putting x= -5y-7 / 8

in equation (2), we get 7x-6y=4

7(-5y-7/8)-6y=4

⇒-35y-49-48y=32

⇒-83y-49=32

⇒-83y=32+49

⇒-83y=81

⇒y= 81 / -83

⇒y= -0.9759→(4)

Now, Putting y= -0.9759 in equation (3), we get

x= -5y-7

x= -5(-0.9759)-7/8

⇒x= 4.8795-7/8

⇒x= -2.1205/8

⇒x= -0.2651

∴x= -0.2651 and y = -0.9759

7 0
3 years ago
Gavin needs $80 to buy a fish tank. He has saved $8 and plans to work as a babysitter to earn $9 per hour. Which inequality show
yuradex [85]
Gavin needs $80 to buy a fish tank. He has saved $8 and plans to work as a babysitter to earn $9 per hour. Which inequality shows the minimum number of hours, n, that Gavin should work as a babysitter to earn enough to buy the fish tank? 8 + 9n ≥ 80, so n ≥ 8 8 + 9n ≤ 80, so n ≤ 8 9n ≥ 80 + 8, so n ≥ 9.8 9n ≤ 80 + 8, so n ≤ 9.8
3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!<br><br> Subract and simplify.
pantera1 [17]

Answer: C

<u>Step-by-step explanation:</u>

  \dfrac{x+1}{x-5} - \dfrac{x-2}{x+3}

= \dfrac{x+1}{x-5}(\dfrac{x+3}{x+3}) - \dfrac{x-2}{x+3}(\dfrac{x-5}{x-5})

= \dfrac{x^{2}+4x+3}{(x-5)(x+3)} - \dfrac{x^{2}-7x+10}{(x-5)(x+3)}

= \dfrac{x^{2}+4x+3-(x^{2}-7x+10)}{(x-5)(x+3)}

= \dfrac{11x-7}{(x-5)(x+3)}

5 0
3 years ago
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