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34kurt
3 years ago
12

A municipal electrical utility charges customers a $15 per month fee plus 12 cents per kilowatt-hour of energy used. Write an eq

uation for a customer's monthly costs, C (in dollars) for electric service as a function of x, the kilowatt-hours used.
Mathematics
1 answer:
ale4655 [162]3 years ago
8 0

Answer:

C(x) = 15 + 12 * x

Step-by-step explanation:

Cost = monthly fee plus cost per hour * hours

C(x) = 15 + 12 * x

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Alexus [3.1K]
7.92 is less than 8
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the answer is less than 88.
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Xelga [282]
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3 years ago
Help please!!!!!!!!!!!!!
Bingel [31]
Combine the 2nd and 3rd equations.  3x will disappear:

 2y + 5z = 7  This is true for any y and z, and is independent of x.
 
                                                            7-5z
Solving for y, 2y = 7 - 5z, so that y = ---------
                                                               2

We have to eliminate x again by using the 1st and 2nd equations:

 -2x - 6y - 2z = -2.  We want the coeff. of x in the first eqn to be -3.  

Therefore, mult. all terms of  -2x - 6y - 2z = -2  by 3/2:

(3/2)(-2x - 6y - 2z = -2) = -3x -9y  -3z =-3

Now add this version of the 1st row to the 2nd row:

  -3x -9y  -3z =-3
   3x +2y +5z = 7
----------------------
         -7y + 2z = 4
                                          7 - 5z
We found earlier that y = ----------, and can elim. y by subst. this fraction into 
                                              2

 -7y + 2z = 4.  Then     -7y + 2z = 4 becomes   -7( (7-5z)/2 ) + 2Z = 4.

Elim. the fraction by mult. all terms by 2:

-7(7-5z) + 4z = 8    which becomes    -49 + 35z + 4z = 8

so that 39z = 57, and so z = 57/39.

Subst. this back into -7y + 2z = 4 to calculate y.  Make a final subst. to calculate x.

Given the choice, I would solve this system using matrices.

Turns out that the solution, using matrices, does not exist.


                                             
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3 years ago
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Answer:

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