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vodomira [7]
3 years ago
12

HELP PLS!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

Step-by-step explanation:

the solutions are options: 2, 3, 4

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Find $ \left(\frac{5}{12}\right)^{4}\left(\frac{12}{15}\right)^{3} $.
vitfil [10]

Question:- Find

\left(\frac{5}{12}\right)^{4}\left(\frac{12}{15}\right)^{3}

Answer:-

\left(\frac{5}{12}\right)^{4}\left(\frac{12}{15}\right)^{3}

Taking power inside the bracket

\frac{5^{4} }{ {12}^{4} }  \times  \frac{ {12}^{3} }{ {15}^{3} }

\frac{ {5}^{4} }{ {12}^{4 - 3} }  \times  \frac{1}{ {(5 \times 3)}^{3} }  \\  \frac{ {5}^{4} }{12}  \times  \frac{1}{ {5}^{ 3 } \times  {3}^{3}  }  \\  \frac{ {5}^{4 - 3} }{12 \times  {3}^{3} }  \\  \frac{5}{4 \times 3 \times  {3}^{3} }  \\  \frac{5}{4 \times  {3}^{4} }  =  \frac{5}{4\times81 }  \\  Answer-> \frac{5}{324}

Power\:Form-> \frac{ 5 }{12 \times {3}^{3} }

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3 years ago
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Answer:

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martin spent 6 hours on homework every day . what percentage of the day did martin spend doing homework ?
Ann [662]
1/4 or .25 because 6 * 4 = 24 so 6 would be a quarter of 24
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4 0
3 years ago
Read 2 more answers
Write x(x-2)+3(2-x) as a product of binomials. Hint: you may want to manipulate (2-x) first. Check to see If you have written an
dmitriy555 [2]

Answer:

x²-5x+6

Step-by-step explanation:

The question is to find product in : x(x-2)+3(2-x)-----------(a)

Make terms in brackets same by introducing a negative sign as;

Collect like terms as : x(x-2) - 3 (x-2)------------ (b)

Note that expression (a) is similar to (b)

Factorize equation (b) as : (x-3)(x-2)

Distribute as : x(x-2) -3 (x-2 ) ------ x²-2x-3x+6

Collect like terms as: x²-5x+6

Final expression : x²-5x+6

Testing with x=5 in original expression

x(x-2)+3(2-x)

5(5-2)+3(2-5)

25-10+6-15

25+6-10-15

31-10-15=6

Using the final expression;

x²-5x+6

5²-5(5)+6

25-25+6

=6

3 0
4 years ago
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