Answer:
Center (-5, 2) and radius 5
Step-by-step explanation:
The equation for a circle is 
Where (h, k) is the center and r is the radius.
Answer:
x = 
Step-by-step explanation:
According to Pythagorean Theorem, the square value of hypotenuse is equal to sum of square value of two legs:
x^2 + 4^2 = 10^2
x^2 + 16 = 100 subtract 16 from both side
x^2 = 84 find the root of both sides
x =
From what we know, p is 20 more than q. So, we can assume p = 20 + q. Q can also be found by subtracting 20 from both sides. So, q = p - 20.
Hope this helped!
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
