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Elena L [17]
3 years ago
8

PLZ HURRYY!!Solve for p.5p – 7 > – 12

Mathematics
1 answer:
Anarel [89]3 years ago
8 0

I am gonna do what you did to me and say its easy.

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Suppose that P(A) = 0.25 and P(B) = 0.40 . If P(A|B)=0.20 , what is P(B|A) ?
Ket [755]

Answer:

  • 0.32

Step-by-step explanation:

<u>Use of formula:</u>

  • P(A and B) = P(A)*P(B|A) and
  • P(A and B) = P(B)*P(A|B)

<u>According to above and based on given:</u>

  • P(A)P(B|A) = P(B)P(A|B)
  • P(B|A) = P(A|B)*P(B)/P(A)
  • P(B|A) = 0.20*0.40/0.25 = 0.32
8 0
3 years ago
Describe how to write 3x+2y=12 in function notation.assume that y represent the dependent variable.
GarryVolchara [31]
To write this function in function notation all you would need to do is rearrange the equation for y.

3x + 2y = 12

3x - 3x + 2y = 12 - 3x

2y = 12 - 3x

2y/2 = 12/2 - 3x/2

Y = 6 - 3/2 X or

Y = -3/2 X + 6.

5 0
3 years ago
Read 2 more answers
An independent-measures research study compares three treatment conditions using a sample of n = 5 in each treatment. For this s
slavikrds [6]

Answer: c. ​10

Step-by-step explanation:

Given : An independent-measures research study compares three treatment conditions using a sample of n = 5 in each treatment.

For this study, the three sample means are, M1 = 1, M2 = 2, and M3 = 3.

Grand mean = \overline{X}=\dfrac{M1+M2+M3}{3} [All sample have equal elements]

=\dfrac{1+2+3}{3}=2

For ANOVA,

SS_{between}=n\sum(M_i-\overline{X})^2 , where i= 1, 2 , 3

SS_{between}=5((1-2)^2+(2-2)^2+((3-2)^2)

SS_{between}=5((-1)^2+(0)^2+((1)^2)= 5(1+1)=10

Hence,the value would be obtained for SS_{between}=10 .

hence, the correct answer = c. ​10

8 0
3 years ago
Triangle BCD is equivalent AG=1.find the perimeter of BCD
Ymorist [56]
AG=1 => BG=3 => CG=sqrt3 => CD = 2sqrt3 => perimeter = 3*CD= 6sqrt3
4 0
4 years ago
7p2-3-3p3 in standard form
Mekhanik [1.2K]

Answer:

-3p^3+7p^2-3

Step-by-step explanation:

7 0
3 years ago
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