It would happen because 5 is 5 4 is 4 3 is 3 2 is 2 1 is 1 and 0 is only one number 0.
Answer:
We have the slope-intercept form of a straight line given by y = mx + b, where m is the slope and b is the y-intercept.
Now, when the slope m is positive, the straight line will slant upward towards the right and when the slope m is negative, the line will slant downwards to the right.
Moreover, the more positive or negative the slope is, the steeper the slant of the corresponding line will be.
The change can be seen in figure 1 below where the slope is changing as 2. 4 and -5.
Further, when the y-intercept b is positive, the line will cross the y-axis above the line y=0 and when the y-intercept b is negative, the line will cross y-axis below y=0.
Moreover, the change in y-intercept will shift the graph of the line in left or right direction.
The shift can be seen below in the second figure, where y-intercept changes from 3, 4 and -5.
Unit vector along the direction v = <3,1,-4> is :
So, unit vector opposing the is :
so, vector of magnitude 3 units in opposite direction from v is :
Hence, this is the required solution.
Answer:
Therefore the required point A(x₁ , y₁) = A( -3 , 4 )
Step-by-step explanation:
Given:
The midpoint of segment AB is M(1,-3)
and B(5,-10),
Let
point A( x₁ , y₁)
point B( x₂ , y₂) ≡ (5 , -10)
M(x , y) = (1 , -3 )
To Find:
point A( x₁ , y₁) = ?
Solution:
M is the midpoint of segment AB. {Given}
BY Mid point Formula we have
Substituting the given values in above equation we get
Therefore the required point A(x₁ , y₁) = A( -3 , 4 )
We know the combined area is 100π, and the combined area includes the white section as well as the orange section.
now, if we take the area of the white circle, and "subtract" it from the combined area, we're in effect, making a whole in the larger circle, and what's leftover is just the orange part, because the white would have been subtracted out,