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2 years ago

I i iii ii need help

Mathematics

1 answer:

san4es73 [151]2 years ago

7 0

Answer:

C or the bottom left one

Step-by-step explanation:

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Given the universal set U = {v, w, x, y, z), and subsets A = {v, w, z} and B = {x, y, z), indicate the roster

lukranit [14]

If U = {v, w, x, y, z} and A = {v, w, z}, then

A' = {x, y}

(A' is the complement of A - it's the set containing all elements of U that are not in A)

If B = {x, y, z}, then

B' = {v, w}

Their their union is

A' U B' = {v, w, x, y}

8 0

2 years ago

Determine the value of c that will result in a perfect square trinomial. <br> w^2+6w+ c =130+c

Genrish500 [490]

Answer:

The value of c that will result in a perfect square trinomial is (3)^2 or 9

The perfect square trinomial is: $(w+3)^2=139$

Step-by-step explanation:

We need to determine the value of c that will result in a perfect square trinomial.

$w^2+6w+ c =130+c$

Perfect square trinomial are of form: $a^2+2ab+b^2=(a+b)^2$

Now, the equation given is:

$w^2+6w+ c =130+c$

Looking at the term 6w, we can write it as 2(w)(3)

We are given: a = w, 2ab = 2(w)(3) so, b will be: (3)^2

So, we will be adding (3)^2 on both sides

$w^2+6w+ c=130+c\\w^2+2(w)(3)+ (3)^2 =130+(3)^2\\The\:left\:side\:becomes: a^2+2ab+b^2\\We\:can\:write\:it\:as: (a+b)^2\\We\:have\:a=w\: and\: b=3\\(w+3)^2=130+9\\(w+3)^2=139$

So, The value of c that will result in a perfect square trinomial is (3)^2 or 9

The perfect square trinomial is: $(w+3)^2=139$

3 0

3 years ago

The circumference of a circle with a radius of 5, using 3.14 for pi, to the nearest tenth

Anuta_ua [19.1K]

Answer:

Your answer is 31.4 units squared

Step-by-step explanation:

By doing 2πr, you'll get your answer.

2*3.14*5 = 2*15.7 = 31.4

3 0

3 years ago

zheka24 [161]

Is there a picture I can see

7 0

3 years ago

-13r + -4r + 14r -9 =-15

deff fn [24]

Answer:

Step-by-step explanation:

-13 x 2 = -26

-4 x 2 = -8

14 x 2 = 28

-26 + -8 + 28 +-9 = -15

have a nice day and mark me brainliest! :)

8 0

3 years ago

Read 2 more answers