<span>For problem 8:
sin A/a sinB/b = sinC/c
so sin50/15 = sinB/12
0.766/15 =sinB/12
0.051066 = sin B/12
sin B = 0.6128
B = 37.79 degrees
sum of angles must equal 180 deg therefore C = 180-50-37.79 = 92.21 degrees and .766/15 = sin92.21/c
.051066= 0.99925/c
c = .99925/0.051066 = 19.567
Problems 9 and 10 can also be done with the same method as problem 8.
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Answer:
2nd and 5th options
Step-by-step explanation:
the solution to a system of equations is at the point of intersection of the 2 lines.
If the lines are parallel then they never intersect and will have no solution.
The slopes m of parallel lines are equal.
The options with equal slopes , both - 2 are the
2nd and 5th options
Four divided by a number n.
I'm sure of it and I hope I helped.
If Keith had 1 1/2 cups, he can't use <span>5 2/3 cups. He cant use more than what he had. There is error in this question.</span>
Answer:
g(0.9) ≈ -2.6
g(1.1) ≈ 0.6
For 1.1 the estimation is a bit too high and for 0.9 it is too low.
Step-by-step explanation:
For values of x near 1 we can estimate g(x) with t(x) = g'(1) (x-1) + g(1). Note that g'(1) = 1²+15 = 16, and for values near one g'(x) is increasing because x² is increasing for positive values. This means that the tangent line t(x) will be above the graph of g, and the estimates we will make are a bit too big for values at the right of 1, like 1.1, and they will be too low for values at the left like 0.9.
For 0.9, we estimate
g(0.9) ≈ 16* (-0.1) -1 = -2.6
g(1.1) ≈ 16* 0.1 -1 = 0.6
