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GREYUIT [131]
3 years ago
12

Solve by the substitution method. 8x + 9y=56 -9x + y = 26​

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

(-2,8)

Step-by-step explanation:

8x + 9y=56

-9x + y = 26​

---------------------------------------------------------------------------------

-9x + y = 26​

    +9x = +9x

y = 9x + 26

---------------------------------------------------------------------------------

8x + 9(9x+26) = 56    <-- substitute for y from above

8x + 81x + 234 = 56

      89x + 234 = 56

               - 234 = - 234

                  89x = - 178

                      x = -2        <--- we got the x value!!

--------------------------------------------------------------------------------

-9x + y = 26​

-9 (-2) + y = 26    <-- substitute for x from above

18 + y = 26

   - 18 = - 18

      y = 8    <-- we got the y value!!

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Assume x = 2.7777777777......equation 1

Now, notice that the repeating digit is 7
 multiply both sides of the equation by 10:
10x = 27.7777777777.......equation 2

Subtract equation 1 from equation 2 as follows:
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Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally
saveliy_v [14]

Answer:

0.8029 = 80.29% probability that the thickness is between 3.0 and 7.0 mm.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 4.6 millimeters (mm) and a standard deviation of 1.5 mm.

This means that \mu = 4.6, \sigma = 1.5

Find the probability that the thickness is between 3.0 and 7.0 mm.

This is the pvalue of Z when X = 7 subtracted by the pvalue of Z when X = 3. So

X = 7

Z = \frac{X - \mu}{\sigma}

Z = \frac{7 - 4.6}{1.5}

Z = 1.6

Z = 1.6 has a pvalue of 0.9452

X = 3

Z = \frac{X - \mu}{\sigma}

Z = \frac{3 - 4.6}{1.5}

Z = -1.07

Z = -1.07 has a pvalue of 0.1423

0.9452 - 0.1423 = 0.8029

0.8029 = 80.29% probability that the thickness is between 3.0 and 7.0 mm.

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