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frosja888 [35]
3 years ago
15

No need to show work just need answer.

Mathematics
1 answer:
RideAnS [48]3 years ago
5 0
Can I have brainliest since u did t put a picture :)
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Write an equation of a parabola that opens to the left, has a vertex at the origin, and a focus at (–9, 0.
Georgia [21]
The standard equation of parabola:

(y-k)²=4p(x-h), with:

a) vertex = (h,k)

b) focus = (h+p, k)

c) directrix = (x=h-p)


Since this parabola has a vertex at (0,0) that means h=k=0

Hence the equation becomes: y²=4px, let's calculate p:
focus is given (-9,0) Remember h+p = -9 & since h=0, then p= -9
===> y²= - 36x
8 0
4 years ago
Dan puts $11 of his allowance in his savings account every week.how many money will he have after 15 weeks
Fittoniya [83]
If you multiply 11 by 15 which is 165 you will get your answer 165$
5 0
3 years ago
2+8+5+9+90=<br>3+45+111=​
Anastasy [175]

Answer:

1) 114

2) 159

Step-by-step explanation:

2+8+5+9+90 = 114

3+45+111 = 159

Hope this helps.

8 0
3 years ago
A quadratic relation has zeros at 3 and –5. The parabola goes through the point (2, –14). What is the equation of the parabola i
olasank [31]

Answer:

\displaystyle  2 {x}^{2}  + 4x - 30 = 0

Step-by-step explanation:

we are given the zeros and a point where it goes through of a quadratic equation

remember that when the roots are given then the function should be

\displaystyle \: y =  a(x -  x_{1})(x -  x_{2})

where a is the leading coefficient and x1 and x2 are the roots

substitute:

\displaystyle y = a(x -  (3))(x -  ( - 5))

simplify:

\displaystyle y = a(x -  3)(x  + 5)

now the given point tells us that when x is 2 y is -14 therefore by using the point we can figure out a

substitute:

\displaystyle a(2 -  3)(2  + 5)  =  - 14

simplify parentheses:

\displaystyle a(  - 1)(7)  =  - 14

simplify multiplication:

\displaystyle  - 7a =  - 14

divide both sides by -7:

\displaystyle  a =  2

altogether substitute:

\displaystyle y = 2(x -  3)(x  + 5)

since it want the equation y should be

\displaystyle  2(x -  3)(x  + 5)  = 0

recall quadratic equation standard form:

\displaystyle   {ax}^{2}  + bx + c = 0

so simplify parentheses:

\displaystyle  2( {x}^{2}  + 2x - 15 )  = 0

distribute:

\displaystyle  2 {x}^{2}  + 4x - 30 = 0

hence,

the equation of the parabola in standard form is <u>2</u><u>x</u><u>²</u><u>+</u><u>4</u><u>x</u><u>-</u><u>3</u><u>0</u><u>=</u><u>0</u>

8 0
3 years ago
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