Answer:
<h3>3y-4x = -6</h3>
Step-by-step explanation:
First get the slope of the given line;
Given the equation of the line 3x+4y=12
Rewrite in standard form y = mx+c where m is the slope;
3x+4y=12
4y = -3x + 12
y = -3x/4 + 12/4
y = -3x/4 + 3
Hence the slope of the given line is -3/4
Since the required line is perpendicular to this line, the slope of the required line will be M = -1/(-3/4) = 4/3
Get the equation:
Substitute M = 4/3 and the point (3,2) into the point slope equation of a line as shown;
y-y0 = m(x-x0)
y - 2 = 4/3(x-3)
Cross multiply
3(y-2) = 4(x-3)
3y - 6 = 4x - 12
3y - 4x = -12 + 6
<em>3y-4x = -6</em>
<em>Hence the required equation of the line is 3y-4x = -6</em>
