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3 years ago

If stitching thread costs $6.50 per foot, how much does 11 feet, 6 inches of thread cost?

Mathematics

1 answer:

andriy [413]3 years ago

8 0

Answer:

Step-by-step explanation:

O.5

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The period T of a pendulum in seconds depends on its length L in feet, and is given by the formula T=

Damm [24]

This is a matter of plugging in. Specifically 7 for L.

T = 2πsqrt(7/32)
T = (6.28319...)(0.46771...)
T is about 2.93871 seconds

4 0

3 years ago

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

What is the approximate area of the circle?

Sophie [7]

Answer:

Step-by-step explanation:

because it is

5 0

3 years ago

Read 2 more answers

An abstract sculpture in the form of a triangle has a base 21 meters and a height of 12 meters. Find the are of the triangle.

charle [14.2K]

The area of a triangle could be determined using the following formula
$\boxed{a= \frac{1}{2} \times b \times h}$

plug in the numbers
$a = \frac{1}{2} \times 21 \times 12$
$a = \frac{1}{2} \times 252$
$a= \frac{252}{2}$
a = 126

The area of the triangle is 126 square meters

8 0

3 years ago

Question

Naya [18.7K]

Answer:

I don't know

Step-by-step explanation:

the answer is 0.2

3 0

3 years ago