If two countries claim the same region, generally, it likely leads to tensions between them, so you know that the answer is D). even without knowing specifically about India and Pakistan.
And it is: India and Pakistan have a very strained relationship and had even some military conflicts and nuclear arms race because of Kashmir.
Answer:Hinduism and Buddhism
Explanation: They developed differently because they came from a foreign country
The answer is: Iran .
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Answer:
See solution and explanation below
Explanation:
a) From;
N/No = (1/2)^t/t1/2
1/8 = (1/2)^t/1.25 * 10^9
(1/2)^3 = (1/2)^t/1.25 * 10^9
3 = t/1.25 * 10^9
t = 3 * 1.25 * 10^9
t = 3.75 * 10^9 years
b)
N/No = (1/2)^40,110/5,730
N/No = (1/2)^7
N/No = 1/128
percentage remaining after 40,110 years = 1/128 * 100 = 0.78%
c) N/200 * 10^-9 = (1/2)^4.26 * 10^9/0.710 * 10^9
N/200 * 10^-9 = (1/2)^6
N/200 * 10^-9 = 1/64
64 N = 200 * 10^-9
N= 3.125 * 10^-9 g
d) Radiocarbon dating can not be used to determine the age of the solar system since the solar system is as old as the universe and was formed billions of years ago. Radiocarbon dating can only be accurately used to obtain the age of objects of plant or animal origin between 1000 - 10000 years old.
Answer:
t = 100 - 5n : rule for amount of money left.
You will have $45 left after using downtown parking 11 times.
Explanation:
The equation for an arithmetic sequence in this case is t = a + dn.
a is the initial value, d is the rate of change, and n is the independent variable.
t is the dependent variable.
In this context, a is the starting budget for parking, d is the amount parking costs each time, n is the number of times you use the parking and t is the amount of money left after each time you use the parking.
Substitute the known values from the problem into the equation.
t = a + dn
t = 100 + (-5)n <= the rate of change is -5 because it's decreasing
t = 100 - 5n
To find the amount of money left after 11 times using downtown parking, substitute n for 11.
t = 100 - 5n
t = 100 - 5(11)
t = 100 - 55
t = 45
You will have $45 left after 11 times parking downtown.