Answer:
7(b^2 -2)(b^2 +2)
Step-by-step explanation:
Factoring the common factor 7 from both terms, you get the difference of squares. That can also be factored.
v = 7(b^4 -4) = 7(b^2 -2)(b^2 +2)
The difference b^2-2 will have irrational factors, so does not meet the problem requirements. This is the factorization over integers.
1.)Substitute numbers for A, B, C (ex. 3,4,5): (3)^2 + (4)^2 = (5)^2
2.)Simplify and Solve: 9+16=25
25=25. Therefore, the Pythagorean Theorem is true.
Let, the integers = x,(x+1)
x*(x+1) = 56
x²+x = 56
x²+x-56 = 0
x²+8x-7x-56=0
x(x+8)-7(x+8)=0
x+8= 0 OR x-7=0
x = -8 OR x = 7
it would be -8 & -7 or 7 & 8
It is 0 because anything multiplied by 0 is 0.
You've given us two equations and asked for an answer.
What you haven't given us is a question.
