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3 years ago

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An account is opened with $1250 at a bank that pays 4.75% interest yearly, write a function A(t) that tells how much money is in

the account after t years

1 answer:

svetlana [45]3 years ago

7 0

Answer:

W

Step-by-step explanation:

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Please answer ASAP! An explanation is a MUST REQUIREMENT in order to receive points and the Brainliest answer. Thank you.

Jet001 [13]

$(\sqrt[3]{x^{2}})^{6}=x^{(2* \frac{1}{3})*6}=x^{ \frac{2}{3}*6 } =x^{4}$

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3 years ago

Read 2 more answers

The likelihood that Sue makes a free throw in basketball is 73%. The likelihood that she makes a 3-point shot is 0.72. Which is

AleksandrR [38]

Answer:

She is more likely to make a free throw in basketball.

Step-by-step explanation:

This is because 73% is equal to .73 and .72 is equal to 72% so thats more common.

5 0

3 years ago

Greta is trying to determine the portion of green candies in various bags of green and yellow candies. Using the information bel

IrinaK [193]

Answer: a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

Step-by-step explanation:

Since we have given that

There are green and yellow candies in each bag.

Bag A: Two thirds of the candies are yellow. What portion of the candies is green?

Part of yellow candies in bag A = $\dfrac{2}{3}$

Part of green candies in bag A would be

$1-\dfrac{2}{3}\\\\=\dfrac{3-2}{3}\\\\=\dfrac{1}{3}$

Bag B: 29 % of the candies are yellow. What portion of the candies is green?

Percentage of candies are yellow = 29%

Portion of candies are green is given by

$1-\dfrac{29}{100}\\\\=1-0.29\\\\=0.71\\\\=\dfrac{71}{100}$

Bag C: 4 out of every 9 candies are yellow. What portion of the candies is green?

Portion of yellow candies = $\dfrac{4}{9}$

Portion of green candies would be

$1-\dfrac{4}{9}\\\\=\dfrac{9-4}{9}\\\\=\dfrac{5}{9}$

Hence, a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

6 0

3 years ago

An equation always, sometimes, never has one solution?

DiKsa [7]

Answer: An equation may have more than one solution, or the solution(s) may be complex, rather than real, but it will always have one solution - and sometimes more than one.

Step-by-step explanation:

3 0

3 years ago

Vsevolod [243]

Answer:

• zero: -4, -4/3, 7

• positive: -4 < x < -4/3 . . . or 7 < x

• negative: x < -4 . . . or -4/3 < x < 7

Step-by-step explanation:

Zeros of the function are at x=-4, -4/3, +7. These are the values that make each of the individual factors be zero. For example, x-7=0 when x=7.

The function will be negative for x-values left of an odd number of zeros. It will be positive for x-values left of an even number of zeros (including left of no zeros, which is to say right of all zeros). This is because the sign of the factor giving rise to the zero changes for x-values on either side of that zero. (This is not true for zeros with even multiplicity, as the sign does not change at those.)

3 0

3 years ago